How do I evaluate the result of a command assigned to a variable??
Example:
var1=`cmd`
rc=$?
rc will be the result of the assignment rather than cmd since it executes after. How do I evaluate the result of the command itself?
Cheers..:confused: (2 Replies)
Hi,
I want to check if a variable has a value assigned to it or not.
I can do following -
cat $Var > File1
if
then
echo "$Var has value"
else
echo "$Var is null"
fi
But I have to check for 3 Variables and I want to wrap it up in couple of unix statements.
Any... (3 Replies)
Hi
I've few shell scripts which are responsible for triggering the continuous builds for a specific module. Each shell script is for a Module. Shell script has some module specific settings in the beginning and then it triggers the builds (which are nothing but some combination of Java programs... (2 Replies)
Hey ,
I'm trying to perform the following command, however it cannot read the variable assigned earlier. I'm not sure why this happen. Please help thanks
while :
do
echo "what's ur name? (if none just press )"
read name
changeName = echo $name | sed "s/on/ey/"
echo $changeName #this... (8 Replies)
I am making of a script that will go through a couple of for loops and create file names based on the values in that loop, however the variable that combines everything is not getting assigned properly:
#! /bin/bash
for imod in K33_j1b_WS9_6
do
for emod in mb2A mb2C mb3A mb3C mb4A... (1 Reply)
The requirement is, there is a log file which contains a huge data. i need to get a particular field out of it by searching with another field.
ex:
2011-03-28 13:00:07,423 : millis=231 q={ call get_data_account(?,?,?,?,?) }, params=
i need to search for the word "get_data_account" in file... (1 Reply)
I am trying to check whether a variable has been assigned on the command line or not.
Here is what I did:
#!/usr/bin/bash
if( $variable == '\0')
{
print "variable was not assigned"
exit
}
else
NF = 2 {print $1, ""}
exit
fi
awk -f question1.awk variable = 58 letters.txt.
So... (3 Replies)
I am more of a newbie, but wanted to post this in this forum as I was afraid no one would look at it in unix forums as it concerns shell scripting. I have a shell script that now runs fine with the exclusion of one line:
x=`su nbadmin -c "ssh -t servery /usr/openv/netbackup/bin/bplist -C... (7 Replies)
Experts,
I'm having problems with the code below.
I'm trying to test $var2 for two different regexs.
I thought it could be done per below, but I'm getting the following error when running.
$ ./test.pl b fed50c0100****
Unescaped left brace in regex is deprecated, passed through in regex; marked... (2 Replies)
Discussion started by: timj123
2 Replies
LEARN ABOUT LINUX
bzexe
BZEXE(1) General Commands Manual BZEXE(1)NAME
bzexe - compress executable files in place
SYNOPSIS
bzexe [ name ... ]
DESCRIPTION
The bzexe utility allows you to compress executables in place and have them automatically uncompress and execute when you run them (at a
penalty in performance). For example if you execute ``bzexe /bin/cat'' it will create the following two files:
-r-xr-xr-x 1 root bin 9644 Feb 11 11:16 /bin/cat
-r-xr-xr-x 1 bin bin 24576 Nov 23 13:21 /bin/cat~
/bin/cat~ is the original file and /bin/cat is the self-uncompressing executable file. You can remove /bin/cat~ once you are sure that
/bin/cat works properly.
This utility is most useful on systems with very small disks.
OPTIONS -d Decompress the given executables instead of compressing them.
SEE ALSO bzip2(1), znew(1), zmore(1), zcmp(1), zforce(1)CAVEATS
The compressed executable is a shell script. This may create some security holes. In particular, the compressed executable relies on the
PATH environment variable to find gzip and some other utilities (tail, chmod, ln, sleep).
BUGS
bzexe attempts to retain the original file attributes on the compressed executable, but you may have to fix them manually in some cases,
using chmod or chown.
BZEXE(1)