11-06-2009
If all the numbers are integers, you can use %d (or %u if always positive) instead of %.f
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi All,
I am trying to check if if column 5 is greater than 90. If greater it will print the term in column 6, else if all are within limit, then it will output "Size is within limit". I can't seem to do that with the below code. The output should only be 1 statement of "Size is within the... (4 Replies)
Discussion started by: Raynon
4 Replies
2. Shell Programming and Scripting
hi all,
i have a problem with my nawk command output below is the description :
nawk $12 == "00008001" { cnt++;cs_cd } END {for(cd in cs_cd) print cd, cs_cd } 2007020814.TDR
output :
133
123
desire output:
133,123,....
please advices
thank you so much (6 Replies)
Discussion started by: bucci
6 Replies
3. Shell Programming and Scripting
Input file1
zone: BAU_SERVER1
C0:50:76:01:C6:20:00:12; 50:06:01:69:3B:20:14:8B;
50:06:01:60:3B:20:14:8B
zone: BAU_SERVER2
C0:50:76:01:C6:20:00:08; 50:06:01:69:3B:20:14:8B;
50:06:01:60:3B:20:14:8B
zone: ... (4 Replies)
Discussion started by: greycells
4 Replies
4. Shell Programming and Scripting
awk experts,
I have in put file with time stamp followed by "," separated data. same patern continues. The output need time stamp in first columns and data total in 2nd columns.
Input file
T 9:15
d0,1,3,3
d1,2,1,1
d2,3,1,5
e1,1,1,1
T 9:30
d0,1,1,1
d1,2,3,2
d3,1,2,1... (10 Replies)
Discussion started by: arv_cds
10 Replies
5. UNIX for Dummies Questions & Answers
hi
i have a awk command with several querys....
awk 'FS="|""; print $4, $5, $6...etc....
$4 gives me the date 20120304
$5 is timestamp 101023
I want to format these in
2012.03.04 or 2012/03/04
10:10:23
but have no idea, if this is possible with format-parameters in the awk... (2 Replies)
Discussion started by: Jazzmatazz
2 Replies
6. UNIX for Dummies Questions & Answers
Hi,
I have this output:
extended device statistics
device r/s w/s kr/s kw/s wait actv svc_t %w %b
sd1 0.0 0.0 0.0 0.0 0.0 0.0 0.0 0 0
sd2 0.1 2.9 2.6 24.8 0.0 0.1 21.0 0 1
sd3 0.1 2.9 2.7 24.8 0.0 ... (9 Replies)
Discussion started by: mjnman
9 Replies
7. Shell Programming and Scripting
Hi Experts, I am trying to sum multiple columns and rows with awk ,
I want the sum of :
1] Horizontal Sum: (rows sum):
2] Vertical Sum: (Column's sum]
details:
# cat file1
10 11 12 13 14 15 16 17 18 19
20 21 22 23 24 25 26 27 28 29
40 31 32 33 34 35 36 37 38 39
70 41 42 43 44... (2 Replies)
Discussion started by: rveri
2 Replies
8. Shell Programming and Scripting
Hi awk experts,
I am getting a strange output , may be it is normal but I am unable to comprehend,
When Using == operator it is showing correct:
# ls -l | awk '{for (i=0;i<=NF;i++) if ( $i =="info" )print $1,$6,$7,$8,$9}'
drwx------ Jan 17 10:44 info
But When using ~ (equal )... (4 Replies)
Discussion started by: rveri
4 Replies
9. Shell Programming and Scripting
Hello all , need help with this ...
Input File
DEV % POOL
0CB4 FBA 2211300 81792 4 IE RAID-5(3+1) R5_EFD100_1
- - 1805376 82 IF RAID-1 M2_FC300_1
- ... (4 Replies)
Discussion started by: greycells
4 Replies
10. Shell Programming and Scripting
Format output with blocks - Awk
ZONESET_A,DBP02_HBA0,DC01,20:00:00:25:b5:b9:a0:28,10,port-channel20,01-VB2
ZONESET_A,DBP02_HBA0,DC01,50:00:14:42:a0:72:74:00,10,fc4/30,O1-CORE-D
ZONESET_A,dc01vb,DC01,20:00:00:25:b5:b0:a0:13,10,fc1/24,01-VB1... (1 Reply)
Discussion started by: greycells
1 Replies
integer(3pm) Perl Programmers Reference Guide integer(3pm)
NAME
integer - Perl pragma to use integer arithmetic instead of floating point
SYNOPSIS
use integer;
$x = 10/3;
# $x is now 3, not 3.33333333333333333
DESCRIPTION
This tells the compiler to use integer operations from here to the end of the enclosing BLOCK. On many machines, this doesn't matter a
great deal for most computations, but on those without floating point hardware, it can make a big difference in performance.
Note that this only affects how most of the arithmetic and relational operators handle their operands and results, and not how all numbers
everywhere are treated. Specifically, "use integer;" has the effect that before computing the results of the arithmetic operators (+, -,
*, /, %, +=, -=, *=, /=, %=, and unary minus), the comparison operators (<, <=, >, >=, ==, !=, <=>), and the bitwise operators (|, &, ^,
<<, >>, |=, &=, ^=, <<=, >>=), the operands have their fractional portions truncated (or floored), and the result will have its fractional
portion truncated as well. In addition, the range of operands and results is restricted to that of familiar two's complement integers,
i.e., -(2**31) .. (2**31-1) on 32-bit architectures, and -(2**63) .. (2**63-1) on 64-bit architectures. For example, this code
use integer;
$x = 5.8;
$y = 2.5;
$z = 2.7;
$a = 2**31 - 1; # Largest positive integer on 32-bit machines
$, = ", ";
print $x, -$x, $x + $y, $x - $y, $x / $y, $x * $y, $y == $z, $a, $a + 1;
will print: 5.8, -5, 7, 3, 2, 10, 1, 2147483647, -2147483648
Note that $x is still printed as having its true non-integer value of 5.8 since it wasn't operated on. And note too the wrap-around from
the largest positive integer to the largest negative one. Also, arguments passed to functions and the values returned by them are not
affected by "use integer;". E.g.,
srand(1.5);
$, = ", ";
print sin(.5), cos(.5), atan2(1,2), sqrt(2), rand(10);
will give the same result with or without "use integer;" The power operator "**" is also not affected, so that 2 ** .5 is always the
square root of 2. Now, it so happens that the pre- and post- increment and decrement operators, ++ and --, are not affected by "use
integer;" either. Some may rightly consider this to be a bug -- but at least it's a long-standing one.
Finally, "use integer;" also has an additional affect on the bitwise operators. Normally, the operands and results are treated as unsigned
integers, but with "use integer;" the operands and results are signed. This means, among other things, that ~0 is -1, and -2 & -5 is -6.
Internally, native integer arithmetic (as provided by your C compiler) is used. This means that Perl's own semantics for arithmetic
operations may not be preserved. One common source of trouble is the modulus of negative numbers, which Perl does one way, but your
hardware may do another.
% perl -le 'print (4 % -3)'
-2
% perl -Minteger -le 'print (4 % -3)'
1
See "Pragmatic Modules" in perlmodlib, "Integer Arithmetic" in perlop
perl v5.12.1 2010-04-26 integer(3pm)