hi,
i have a simple question:
in hpux 11i;
this cmd :
cat mailtest |grep sekar >test1
gives the output file with the name test1.
i want to remove the line which contains the "sekar" and put the result in the new file....
what is the command for that?.. (2 Replies)
Hi
Is there a way to cut the last two characters off a word or number given that this word or number can be of varying length?
I have tried something like
TEST=`echo $OLD | cut -c 1-5`
where $OLD is a variable containing a number like 1234567 which gives a result of 12345. This is fine... (4 Replies)
Hi, I'm very new to scripting.
grep $s $filename | awk '{print $2}' | cut -c 1-8
How can I optimize this using a single awk?
I tried:
awk '/$s/ {print $2}' $filename | cut -c 1-8
However didn't work, I think the awk is not recognizing $s and the verbal is something else. (6 Replies)
I have been reading for a few hours trying to educate myself enough to accomplish this task, so please know I have performed some research. Unfortunately, I am not a *NIX scripting expert, or a coder. I come from a network background instead.
SO, here is my desired outcome. I have some Cisco... (5 Replies)
Hi,
From the file "example" with lines like below, I need the int value associated with ENG , i.e, 123
SUB: ENG123, GROUP 1
SUB: HIS124, GROUP 1
..
..
Normally , i do
grep ENG example | cut -d ' ' -f 2 | cut -c 4-6
Is it possible to do it in simpler way using awk/sed ?
... (5 Replies)
hi people,
I have a text file containing data, seperated by TAB. I want to process this tab'ed data as variable. how can I assign this?
Ex:
Code:
11aaa 12000 13aaa 14aaa 15aaa 16aaa 17aaa
21aaa 22000 23aaa 24aaa 25aaa 26aaa 27aaa
31aaa 32000 33aaa 34aaa 35aaa 36aaa 37aaa... (1 Reply)
not sure how to do it. wan't to delete it using cut and grep ince i would use it in the shell.
but how must the command be?
grep "64.233.181.103 wwwGoogle.com" /etc/hosts | cut -d
the delimeter is just a space. can you help meplease. :D (1 Reply)
This is my command-line code in my script,
passwd=`grep $passwd $userfile | cut -f2 -d: login_users > retrieve`
the
cut -f2 -d: login_users > retrieve
searches and prints the whole column two. what I need is one of the items in the column two only.. what option can I add to my cut... (2 Replies)
I have a file and need to only select users that have a shell of “/bin/bash” in the line using awk or sed please help (4 Replies)
Discussion started by: boyboy1212
4 Replies
LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS -e-e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)