hi,
i have a simple question:
in hpux 11i;
this cmd :
cat mailtest |grep sekar >test1
gives the output file with the name test1.
i want to remove the line which contains the "sekar" and put the result in the new file....
what is the command for that?.. (2 Replies)
Hi
Is there a way to cut the last two characters off a word or number given that this word or number can be of varying length?
I have tried something like
TEST=`echo $OLD | cut -c 1-5`
where $OLD is a variable containing a number like 1234567 which gives a result of 12345. This is fine... (4 Replies)
Hi, I'm very new to scripting.
grep $s $filename | awk '{print $2}' | cut -c 1-8
How can I optimize this using a single awk?
I tried:
awk '/$s/ {print $2}' $filename | cut -c 1-8
However didn't work, I think the awk is not recognizing $s and the verbal is something else. (6 Replies)
I have been reading for a few hours trying to educate myself enough to accomplish this task, so please know I have performed some research. Unfortunately, I am not a *NIX scripting expert, or a coder. I come from a network background instead.
SO, here is my desired outcome. I have some Cisco... (5 Replies)
Hi,
From the file "example" with lines like below, I need the int value associated with ENG , i.e, 123
SUB: ENG123, GROUP 1
SUB: HIS124, GROUP 1
..
..
Normally , i do
grep ENG example | cut -d ' ' -f 2 | cut -c 4-6
Is it possible to do it in simpler way using awk/sed ?
... (5 Replies)
hi people,
I have a text file containing data, seperated by TAB. I want to process this tab'ed data as variable. how can I assign this?
Ex:
Code:
11aaa 12000 13aaa 14aaa 15aaa 16aaa 17aaa
21aaa 22000 23aaa 24aaa 25aaa 26aaa 27aaa
31aaa 32000 33aaa 34aaa 35aaa 36aaa 37aaa... (1 Reply)
not sure how to do it. wan't to delete it using cut and grep ince i would use it in the shell.
but how must the command be?
grep "64.233.181.103 wwwGoogle.com" /etc/hosts | cut -d
the delimeter is just a space. can you help meplease. :D (1 Reply)
This is my command-line code in my script,
passwd=`grep $passwd $userfile | cut -f2 -d: login_users > retrieve`
the
cut -f2 -d: login_users > retrieve
searches and prints the whole column two. what I need is one of the items in the column two only.. what option can I add to my cut... (2 Replies)
I have a file and need to only select users that have a shell of “/bin/bash” in the line using awk or sed please help (4 Replies)
Discussion started by: boyboy1212
4 Replies
LEARN ABOUT DEBIAN
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)