11-03-2009
sed command issue
Hi everybody,
I have come across a typical problem:
I need to use sed command to replace an apostrophe but it is saying no match found in the error
sed -e 's/`/'/g' ...but it is not working. Can you please tell me how to use this apostrophe in this sed command please. Thanks.
Rubin
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hello ,
I am trying to replace a word :: complete to Failed .
work: complete
Sed command which i am using is given below ::
sed s/work: complete/Failed/g temp1.txt > temp2.txt (Sed command is grabled if i use the above .. because of space which is there between work: and complete. I... (6 Replies)
Discussion started by: raghav1982
6 Replies
2. UNIX Desktop Questions & Answers
Hi,
I have to replace the character AL2 with AL16 which I have in one of my text file .
I used the sed command like this
sed 's/sed 's/AL2/AL16/g' test_carr.dat>test_carr1.dat
But it is not replacing this value to the output file.
The test_carr.dat file contains data like this
cat... (1 Reply)
Discussion started by: kavithakuttyk
1 Replies
3. UNIX for Dummies Questions & Answers
Hello,
I want to remove the / found when executing the date command. When I use: date +%D | sed 's/\///'
I get: 1105/09
I tried: date +%D | sed 's/\*$///'
I need to remove all / from the date command, but it does not seem to work (5 Replies)
Discussion started by: mojoman
5 Replies
4. Shell Programming and Scripting
I need to search for a keyword UTF-16 in a list of files if that keyword is found then i need to convert the file to UTF-8 format using iconv command.
After this i should substitute the UTF-16 keyword inside the file to UTF-8.
Please suggest how to do this in shell scripting. (11 Replies)
Discussion started by: Shruthi8818
11 Replies
5. Shell Programming and Scripting
I ran one the script in debug mode in linux and have a problem
ret='$prmAttunityUser=ais'
Now i need to remove $ from this '$prmAttunityUser=ais' so i had added a sed command like this sed 's/$//g' but its not working could you all please help me with an alternate command
I want the output... (3 Replies)
Discussion started by: vee_789
3 Replies
6. Shell Programming and Scripting
Hi All,
I am trying to use a variable within the sed command but I am not able to get the output.
When I am using the following command (without variable) its working fine:
sed -n '/2011\/12\/10 18:11:11./,$p' < Log.txt > Delta_Log.txt
But when I am putting the value 2011\/12\/10... (4 Replies)
Discussion started by: acoomer
4 Replies
7. Shell Programming and Scripting
I have a file that contains lines like this:
allgroups: cn=Role1,cn=groups,o=xyz,st=mn,c=us
allgroups: cn=Role1,cn=groups,o=xyz,st=mn,c=us
I want to remove the string :
,cn=groups,o=xyz,st=mn,c=us
and so I tried to use SED. i tried to assign it to a variable and use it:
... (3 Replies)
Discussion started by: vskr72
3 Replies
8. UNIX for Dummies Questions & Answers
Hi,
I want to use a code like
sed -n "1,9988p" filename | wc -l
I tried
from=1
till=9988
sed -n "/$from/,/$till/p" filename |wc -l
Issue:
sed -n "1,9988p" filename | wc -l -- Returns 9988 rows
But
sed -n "/$from/,/$till/p" filename |wc -l # Returns > 9988 rows(Complete file)
I... (2 Replies)
Discussion started by: Gurkamal83
2 Replies
9. Shell Programming and Scripting
Hi,
I am using sed command to extract data from my log file for a certain time interval. From and To "time" are my input arguments.
Now if i use the sed command on command line. I get the desired results and If i use it in script.It fails.
sed command as command line:
sed -n '/04-Mar-2015... (6 Replies)
Discussion started by: oberoi1403
6 Replies
10. Shell Programming and Scripting
Hi,
I have a script that replaces one string with the other in all files under the specified directory.
!/bin/bash
# **************** Change Variables Here ************
startdirectory="/opt/app/properties/tmp_new"
searchterm="Oracle/Middleware/"
replaceterm=""
#... (1 Reply)
Discussion started by: mohtashims
1 Replies
LEARN ABOUT DEBIAN
shtool-subst
SHTOOL-SUBST.TMP(1) GNU Portable Shell Tool SHTOOL-SUBST.TMP(1)
NAME
shtool-subst - GNU shtool sed(1) substitution operations
SYNOPSIS
shtool subst [-v|--verbose] [-t|--trace] [-n|--nop] [-w|--warning] [-q|--quiet] [-s|--stealth] [-i|--interactive] [-b|--backup ext]
[-e|--exec cmd] [-f|--file cmd-file] [file] [file ...]
DESCRIPTION
This command applies one or more sed(1) substitution operations to stdin or any number of files.
OPTIONS
The following command line options are available.
-v, --verbose
Display some processing information.
-t, --trace
Enable the output of the essential shell commands which are executed.
-n, --nop
No operation mode. Actual execution of the essential shell commands which would be executed is suppressed.
-w, --warning
Show warning on substitution operation resulting in no content change on every file. The default is to show a warning on substitution
operations resulted in no content change on all files.
-q, --quiet
Suppress warning on substitution operation resulting in no content change.
-s, --stealth
Stealth operation. Preserve timestamp on file.
-i, --interactive
Enter interactive mode where the user has to approve each operation.
-b, --backup ext
Preserve backup of original file using file name extension ext. Default is to overwrite the original file.
-e, --exec cmd
Specify sed(1) command directly.
-f, --file cmd-file
Read sed(1) command from file.
EXAMPLE
# shell script
shtool subst -i -e 's;(c) ([0-9]*)-2000;(c) 1-2001;' *.[ch]
# RPM spec-file
%install
shtool subst -v -n
-e 's;^(prefix=).*;1 $RPM_BUILD_ROOT%{_prefix};g'
-e 's;^(sysconfdir=).*;1 $RPM_BUILD_ROOT%{_prefix}/etc;g'
`find . -name Makefile -print`
make install
HISTORY
The GNU shtool subst command was originally written by Ralf S. Engelschall <rse@engelschall.com> in 2001 for GNU shtool. It was prompted
by the need to have a uniform and convenient patching frontend to sed(1) operations in the OpenPKG package specifications.
SEE ALSO
shtool(1), sed(1).
18-Jul-2008 shtool 2.0.8 SHTOOL-SUBST.TMP(1)