I am trying to use awk and its split function to get the number of tokens in a string that are seperated by underscores.
ex_alex_is_testing_this_script_ex would return 7. It works when I directly put the string in. However, I can not get it to work when I try to refer to a variable used earlier... (2 Replies)
I have gone through all the threads in the forum and tested out different things. I am trying to split a 3GB file into multiple files. Some files are even larger than this.
For example:
split -l 3000000 filename.txt
This is very slow and it splits the file with 3 million records in each... (10 Replies)
i have these values inside variable $blah
BUNGA TERATAI 3 5055 ITH 1 0 0 0 1 1
JADE TRADER 143W ITH 4 0 0 0 4 4
MOL SPLENDOR 0307A ITH 3 0 0 0 3 3
so how do I split them into array with the... (4 Replies)
Hi,
I have a variable with the value "hello world". I want to split this variable into two, so that i can write "hello" into one variable and "world" into another.
Any idea how to do this?
Thanks,
Sri (11 Replies)
Hello,
I have a paramter $param consisting just of two literals and want to split it into two parameters, so I can combine it to a new parameter <char1><string><char2>, but the following code didn't work:
tmp_PARAM_1=cut -c1 $PARAM
tmp_PARAM_2=cut -c2 $PARAM... (2 Replies)
Dear all,
I have basic knowledge of Unix script and her I am trying to process variable length and variable format CSV file.
The file length will depend on the numbers of Earnings/Deductions/Direct Deposits.
And
The format will depend on whether it is Earnings/Deductions or Direct Deposits... (2 Replies)
The requirement is, there is a log file which contains a huge data. i need to get a particular field out of it by searching with another field.
ex:
2011-03-28 13:00:07,423 : millis=231 q={ call get_data_account(?,?,?,?,?) }, params=
i need to search for the word "get_data_account" in file... (1 Reply)
Hi,
I have the following lines that I would like to see in an array for easy comparisons and printing:
Example 1:
field1,field2,field3,field4,field5
value1,value2,value3,value4,value5Example 2:
field1,field3,field4,field2,field5,field6,field7... (7 Replies)
Hello;
I have a file consists of 4 columns separated by tab. The problem is the third fields. Some of the them are very long but can be split by the vertical bar "|". Also some of them do not contain the string "UniProt", but I could ignore it at this moment, and sort the file afterwards. Here is... (5 Replies)
Hello,
I need to split a file by number of records and rename each split file with actual filename pre-pended with 3 digit split number.
What I have tried is the below command with 2 digit numeric value
split -l 3 -d abc.txt F (# Will Produce split Files as F00 F01 F02)
How to produce... (19 Replies)
Discussion started by: techedipro
19 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)