10-30-2009
Using sort command to get numeric ascending order
HI everyone,
I am trying to use the unix sort command to get a list of numbers sorted in ascending order but having trouble in getting it to work.
An example of this issue would be when i am trying to sort the following three
number each on a different line "1" , "2" and "116" the sort command list the
results in the order 1,116,2
i want it to sort it as 1,2,116.
Is there any option in sort command that will help me achieve this?
Regards
-w
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look(1) General Commands Manual look(1)
NAME
look - Finds lines in a sorted list
SYNOPSIS
look [-df] [-tcharacter] string [file]
The look command prints all lines in a sorted file that begin with string.
OPTIONS
Uses dictionary order; only letters, digits, tabs, and spaces are used in comparisons. Searches without regard to case; treats uppercase
and lowercase as equivalent. Ignores character and characters following it in the search string. If you specify look -tC ABCDE, the
string ABCDE would become (in effect) AB, with CDE being ignored. This option is primarily for shell scripts, in which more than one
string is being processed.
DESCRIPTION
If no file is specified, look searches in the system word list /usr/share/dict/words, with the options -df assumed by default.
The look command uses binary search.
The -d and -f options affect comparisons as in sort.
NOTES
In order to use the -f option, you must first sort file with the sort -f command; otherwise, look displays only lowercase items.
If you do not specify -f, but specify a file (such as /usr/share/dict/words) that has been sorted with sort -f, look may not produce any
output.
EXAMPLES
To search a sorted file called sortfile for all lines that begin with the string as, enter: look as sortfile To search the system word list
for all words beginning with smi, enter: look smi
This might result in: smile smirk smith smithereens Smithfield Smithson smithy smitten
FILES
System word list.
SEE ALSO
Commands: grep(1), sort(1), spell(1)
look(1)