Sponsored Content
Top Forums Shell Programming and Scripting How to print variable value using file. Post 302366382 by quirkasaurus on Thursday 29th of October 2009 10:43:22 AM
Old 10-29-2009
well.... you have to store the variable you want in a file somewhere.

when you say "CGI", I'm assuming you mean through apache and perl.

So you write your "#year=value" in a file somewhere.
Make sure that "world" has read access to this file.

What I wrote goes into a script that apache accesses:

http://myserver.com/cgi-bin/quirks.pl

something like that....
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

print the name of variable

How can I pass the name of the variable inside a for statment I have a script something like below: classA=12 classB=14 classC=16 # classD = 20 all_class="classA classB classC" for i in $all_class do echo $i = $($i) #<---- this one not work #echo $i = $(echo $i) ... (1 Reply)
Discussion started by: sun-guy
1 Replies

2. Shell Programming and Scripting

print variable in file using awk

hi, i have store variable in $var i want to print it in $3 of file using awk. how can i do it? file : var1,var2,var3 var5,var6,var7 var8,var9,var10 . . . i want to print $var in $3 ( for example var3 or var7 or var10) thanks (3 Replies)
Discussion started by: kamel.seg
3 Replies

3. Shell Programming and Scripting

awk print redirection to variable file name

Hello, i need to redirect the output of print to a variable file name: #This is normal awk '{ print $17 > "output.txt" }' input #I need something like this awk '{ print $17 > "output_${25}.txt" }' input how to format the output file name to contain a variable? (6 Replies)
Discussion started by: nazeeb
6 Replies

4. Shell Programming and Scripting

Print arguments with the help of variable

Let's say I want to print the arguments $4 till $#, how can I do this? $# contains the number of arguments $@ contain all the arguments as string What i need is something like for i in $4_till_$#; do #do something with $i convert $i ~/$output done The first 3 arguments are used as options... (6 Replies)
Discussion started by: hakermania
6 Replies

5. Shell Programming and Scripting

awk print variable

I have list of files: ls a.pdf b.pdf c.pdf and so on... and I have a file like this: cat file1 apple mango pear and so on... I want to rename my file like this: (7 Replies)
Discussion started by: zorrox
7 Replies

6. Shell Programming and Scripting

awk print using a variable

hey, just want to ask how to do this. ex. g="hi i am john" h=`echo $g | awk '{print $2}'` echo $h OUTPUT is 'i' What if I want to use a variable instead of using '2', how do I do that? Because this one does not work: a=2 h=`echo $g | awk '{print ${$a}}'` this one also does not... (3 Replies)
Discussion started by: h0ujun
3 Replies

7. Shell Programming and Scripting

awk print variable then fields in variable

i have this variable: varT="1--2--3--5" i want to use awk to print field 3 from this variable. i dont want to do the "echo $varT". but here's my awk code: awk -v valA="$varT" "BEGIN {print valA}" this prints the entire line. i feel like i'm so close to getting what i want. i... (4 Replies)
Discussion started by: SkySmart
4 Replies

8. Shell Programming and Scripting

To print value for a $variable inside a $variable or file

Hi guys, I have a file "abc.dat" in below format: FILE_PATH||||$F_PATH TABLE_LIST||||a|b|c SYST_NM||||${SRC_SYST} Now I am trying to read the above file and want to print the value for above dollar variables F_PATH and SRC_SYST. The problem is it's reading the dollar variables as... (5 Replies)
Discussion started by: abcabc1103
5 Replies

9. Shell Programming and Scripting

awk to lookup stored variable in file and print matching line

The bash bash below extracts the oldest folder from a directory and stores it in filename That result will match a line in bold in input. In the matching line there is an_xxx digit in italics that (once the leading zero is removed) will match a line in link. That is the lint to print in output.... (2 Replies)
Discussion started by: cmccabe
2 Replies

10. Shell Programming and Scripting

How to print contents of file when the file path is in a variable?

The file f1 contains the text "body" (shell prompt is "$"): $ cat ~/path/f1 body How to print contents of f1 when the f1 path is in a variable? Here is my failed attempt: $ f1="~/path/f1" $ echo $f1 ~/path/f1 $ cat $f1 cat: '~/path/f1': No such file or directory (2 Replies)
Discussion started by: wolfv
2 Replies
Template::Plugin::URL(3)				User Contributed Perl Documentation				  Template::Plugin::URL(3)

NAME
Template::Plugin::URL - Plugin to construct complex URLs SYNOPSIS
[% USE url('/cgi-bin/foo.pl') %] [% url(debug = 1, id = 123) %] # ==> /cgi/bin/foo.pl?debug=1&amp;id=123 [% USE mycgi = url('/cgi-bin/bar.pl', mode='browse', debug=1) %] [% mycgi %] # ==> /cgi/bin/bar.pl?mode=browse&amp;debug=1 [% mycgi(mode='submit') %] # ==> /cgi/bin/bar.pl?mode=submit&amp;debug=1 [% mycgi(debug='d2 p0', id='D4-2k[4]') %] # ==> /cgi-bin/bar.pl?mode=browse&amp;debug=d2%20p0&amp;id=D4-2k%5B4%5D DESCRIPTION
The "URL" plugin can be used to construct complex URLs from a base stem and a hash array of additional query parameters. The constructor should be passed a base URL and optionally, a hash array reference of default parameters and values. Used from with a template, it would look something like the following: [% USE url('http://www.somewhere.com/cgi-bin/foo.pl') %] [% USE url('/cgi-bin/bar.pl', mode='browse') %] [% USE url('/cgi-bin/baz.pl', mode='browse', debug=1) %] When the plugin is then called without any arguments, the default base and parameters are returned as a formatted query string. [% url %] For the above three examples, these will produce the following outputs: http://www.somewhere.com/cgi-bin/foo.pl /cgi-bin/bar.pl?mode=browse /cgi-bin/baz.pl?mode=browse&amp;debug=1 Note that additional parameters are separated by '"&amp;"' rather than simply '"&"'. This is the correct behaviour for HTML pages but is, unfortunately, incorrect when creating URLs that do not need to be encoded safely for HTML. This is likely to be corrected in a future version of the plugin (most probably with TT3). In the mean time, you can set $Template::Plugin::URL::JOINT to "&" to get the correct behaviour. Additional parameters may be also be specified to the URL: [% url(mode='submit', id='wiz') %] Which, for the same three examples, produces: http://www.somewhere.com/cgi-bin/foo.pl?mode=submit&amp;id=wiz /cgi-bin/bar.pl?mode=browse&amp;id=wiz /cgi-bin/baz.pl?mode=browse&amp;debug=1&amp;id=wiz A new base URL may also be specified as the first option: [% url('/cgi-bin/waz.pl', test=1) %] producing /cgi-bin/waz.pl?test=1 /cgi-bin/waz.pl?mode=browse&amp;test=1 /cgi-bin/waz.pl?mode=browse&amp;debug=1&amp;test=1 The ordering of the parameters is non-deterministic due to fact that Perl's hashes themselves are unordered. This isn't a problem as the ordering of CGI parameters is insignificant (to the best of my knowledge). All values will be properly escaped thanks to some code borrowed from Lincoln Stein's "CGI" module. e.g. [% USE url('/cgi-bin/woz.pl') %] [% url(name="Elrich von Benjy d'Weiro") %] Here the spaces and ""'"" character are escaped in the output: /cgi-bin/woz.pl?name=Elrich%20von%20Benjy%20d%27Weiro An alternate name may be provided for the plugin at construction time as per regular Template Toolkit syntax. [% USE mycgi = url('cgi-bin/min.pl') %] [% mycgi(debug=1) %] AUTHOR
Andy Wardley <abw@wardley.org> <http://wardley.org/> COPYRIGHT
Copyright (C) 1996-2007 Andy Wardley. All Rights Reserved. This module is free software; you can redistribute it and/or modify it under the same terms as Perl itself. SEE ALSO
Template::Plugin perl v5.12.1 2008-11-13 Template::Plugin::URL(3)
All times are GMT -4. The time now is 10:05 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy