Hi,
I have a script that at one point prints to a file as follows:
printf -- $2 > ~/.mydir/$1
The idea is to print to a hidden directory .mydir in my home directory. I've already sanitized the inputs and $1 is in the format path1/path2/filename and $2 is some user input.
When I run this... (2 Replies)
Dear Friends, we have one ST 6140 storage in our data center.The structure is like that, virtual disk vdisk(RAID-5) was created using 7 hard disks and the vdisk is divided in to 4 volumes each have 1TB of size.These 4 volumes are mapped to solaris 9 server and created RAID 0 using SVM and is... (1 Reply)
Say you have this numeric variable that can be set by the user but you never want it to leave a certain range when it gets printed. How could you use parameter expansion such that it will never expand outside of that boundary? Thanks
---------- Post updated at 11:09 PM ---------- Previous update... (3 Replies)
I have a bunch of files which I need to transfer to another location... and some of these I need to skip.
For e.g. let us say the files are:
cust_abc.dat
cust_xyz.dat
cust_def.dat
and I only want to move the first two.
I want to do something like:
cp cust_.dat <target>
... (1 Reply)
Hi,
I'm trying to figure out whether some files exist. Locations of those file are stored in a plain text file called temp.txt in this way:
All environment variables ($LIB_HOME and $ORACLE_HOME) have been set using export command.
Then I do:
while read line; do ] && echo "OK ==> $line" ||... (6 Replies)
Hello.
I cannot write a command without using eval.
Any help is welcome
Note 1 : What does the function SOMETHING has no importance.
Note 2 : What does the command find has no importance.
It is an expansion variable problem : where to put or or or anythings else
What works (FILTRE_1... (8 Replies)
(Using Bash 4.4)
When I write something like dir="~/dox"
ls $dir then I get the message that the directory '~/docs' does not exist. I understand that the tilde is not expanded at the time of the above assignment because of the quotes. But why is it not expanded at the time when the ls command is... (2 Replies)
Hello All,
Could you please do help me here as I would like to perform parameter expansion in shell over a parameter expansion.
Let's say I have following variable.
path="/var/talend/nat/cdc"
Now to get only nat I could do following.
path1="${path%/*}"
path1="${path1##*/}"
Here... (8 Replies)
Discussion started by: RavinderSingh13
8 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)