Sponsored Content
Top Forums Shell Programming and Scripting date and time in mm/dd/yyyy hh:mm format Post 302365805 by dr.house on Wednesday 28th of October 2009 05:43:03 AM
Old 10-28-2009
Code:
[house@leonov] echo "This was sent by Ezzat on 10/15/2009 12:48 ....." \
[............] | egrep -o "[0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}"
10/15/2009 12:48

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

sed to display date in dd/mm/yyyy format

Hi I have a sed command sed -e "s/sub_date/=$(date +"%d/%m/%Y")/" sub_create_tmp I want to substitute with the current date in dd/mm/yyyy format . But the result is an error " cannot parse " . Pls help . sars (2 Replies)
Discussion started by: sars
2 Replies

2. UNIX for Dummies Questions & Answers

Format date from MM/DD/YYYY to YYYYMMDD

I have a file with some date columns in MM/DD/YYYY format: SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458| And I want to convert the date format to: ... (5 Replies)
Discussion started by: ChicagoBlues
5 Replies

3. Shell Programming and Scripting

Date difference between 2 dates in 'yyyy-mm-dd hh:mm:ss' format

Hi all, I know this may have already been asked but hey ho... i have two dates in the 'yyyy-mm-dd hh:mm:ss' format. '2009-01-03 01:00:00' '2009-04-05 00:00:00' How can i, in shell script determine their differences? Please note, the time may not be available, so please suggest both... (4 Replies)
Discussion started by: muay_tb
4 Replies

4. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

5. Shell Programming and Scripting

Need date in the format [mm dd yyyy hh AM/PM]

could you please help be on the below code .. Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:.. cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'` pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID... (2 Replies)
Discussion started by: karthicss
2 Replies

6. Shell Programming and Scripting

need code for date which is in yyyy-mm-dd format

Hi, I am having one log files. contains som data according to date. And it is going to append .Eg:abc.log contains below data 2011-10-19 abjhgj 2011-10-19 gjhgjgj 2011-10-20 hhhjh 2011-10-20 hhhhjj 2011-10-21 gg . . . 2011-11-24 yyy from log files i want catch only... (2 Replies)
Discussion started by: aish11
2 Replies

7. Shell Programming and Scripting

Convert any date format into yyyy/mm/dd

How can I convert any user inputted date into yyyy/mm/dd ? For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance this is... (1 Reply)
Discussion started by: ZeroHedge
1 Replies

8. Shell Programming and Scripting

Date Format MM/DD/YYYY

I am changing epoch times to dates. I was able to do the following: echo "$varx" | gawk '{print strftime("%c", $0)}' Mon Dec 31 16:26:40 2012 This changes the epoch date (which is what varx is) into localtime. However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
Discussion started by: newbie2010
2 Replies

9. Shell Programming and Scripting

How to get last 12 month date in YYYY.MM format?

I need the date format in YYYY.MM format and I am able to get current month date as well as previous month date with below command PM=`date +'%Y.%m' -d 'last month'` CM=`date +'%Y.%m' -d 'now'` but I need to get YYYY.MM date format for previous 12 months so could you please help me how I get... (2 Replies)
Discussion started by: Amit Joshi
2 Replies

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file... (3 Replies)
Discussion started by: Roozo
3 Replies
ZIPGREP(1L)															       ZIPGREP(1L)

NAME
zipgrep - search files in a ZIP archive for lines matching a pattern SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...] DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1). ARGUMENTS
pattern The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe suffix (if any) explicitly. [file(s)] An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP archive are searched. Regular expressions (wildcards) may be used to match multiple members: * matches a sequence of 0 or more characters ? matches exactly 1 character [...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end- ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within the brackets is complemented (that is, anything except the characters inside the brackets is considered a match). (Be sure to quote any character that might otherwise be interpreted or modified by the operating system.) [-x xfile(s)] An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'), this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories. Without the -x option, all C source files in all directories within the zipfile would be searched. OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1). SEE ALSO
egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L) URL
The Info-ZIP home page is currently at http://www.info-zip.org/pub/infozip/ or ftp://ftp.info-zip.org/pub/infozip/ . AUTHORS
zipgrep was written by Jean-loup Gailly. Info-ZIP 20 April 2009 ZIPGREP(1L)
All times are GMT -4. The time now is 04:32 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy