Hi
I have a sed command
sed -e "s/sub_date/=$(date +"%d/%m/%Y")/" sub_create_tmp
I want to substitute with the current date in dd/mm/yyyy format .
But the result is an error " cannot parse " .
Pls help .
sars (2 Replies)
I have a file with some date columns in MM/DD/YYYY format:
SMPBR|DUP-DO NOT USE|NEW YORK||16105|BA5270715|6/6/2007 |MWERNER|109||||JOHN||SMITH|MD|72211118||||||74559|21 WILMINGTON RD||D|11/6/2003|SL# MD CONTACT-LIZ RICHARDS|||0|Y|N||1411458|
And I want to convert the date format to:
... (5 Replies)
Hi all,
I know this may have already been asked but hey ho...
i have two dates in the 'yyyy-mm-dd hh:mm:ss' format.
'2009-01-03 01:00:00'
'2009-04-05 00:00:00'
How can i, in shell script determine their differences?
Please note, the time may not be available, so please suggest both... (4 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
could you please help be on the below code ..
Requirement is when i pass the parameter(for below 2) i should get current time -2 hours in the format :wall:..
cur_dt=`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID -P $PASSWD -h -C"select getdate()" | sed '2d'`
pr_dt="`$ICEBIN/sqsh -S$DSQUERY -U $BATCHID... (2 Replies)
Hi,
I am having one log files. contains som data according to date. And it is going to append .Eg:abc.log contains below data
2011-10-19 abjhgj
2011-10-19 gjhgjgj
2011-10-20 hhhjh
2011-10-20 hhhhjj
2011-10-21 gg
.
.
.
2011-11-24 yyy
from log files i want catch only... (2 Replies)
How can I convert any user inputted date into yyyy/mm/dd ?
For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc
But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance
this is... (1 Reply)
I am changing epoch times to dates. I was able to do the following:
echo "$varx" | gawk '{print strftime("%c", $0)}'
Mon Dec 31 16:26:40 2012
This changes the epoch date (which is what varx is) into localtime.
However, my problem is that I only want 12/31/2012 and not the Mon Dec 31... (2 Replies)
I need the date format in YYYY.MM format and I am able to get current month date as well as previous month date with below command
PM=`date +'%Y.%m' -d 'last month'`
CM=`date +'%Y.%m' -d 'now'`
but I need to get YYYY.MM date format for previous 12 months so could you please help me how I get... (2 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
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lzegrep
XZGREP(1) XZ Utils XZGREP(1)NAME
xzgrep - search compressed files for a regular expression
SYNOPSIS
xzgrep [grep_options] [-e] pattern file...
xzegrep ...
xzfgrep ...
lzgrep ...
lzegrep ...
lzfgrep ...
DESCRIPTION
xzgrep invokes grep(1) on files which may be either uncompressed or compressed with xz(1), lzma(1), gzip(1), or bzip2(1). All options
specified are passed directly to grep(1).
If no file is specified, then the standard input is decompressed if necessary and fed to grep(1). When reading from standard input,
gzip(1) and bzip2(1) compressed files are not supported.
If xzgrep is invoked as xzegrep or xzfgrep then egrep(1) or fgrep(1) is used instead of grep(1). The same applies to names lzgrep, lze-
grep, and lzfgrep, which are provided for backward compatibility with LZMA Utils.
ENVIRONMENT
GREP If the GREP environment variable is set, xzgrep uses it instead of grep(1), egrep(1), or fgrep(1).
SEE ALSO grep(1), xz(1), gzip(1), bzip2(1), zgrep(1)Tukaani 2009-07-05 XZGREP(1)