I am not an expert in awk. So i need more help. I have a variable named "VAR1" that stores a floating point number. I want to compare it with "12".
What should be the corresponding code in awk.
For that, you don't need awk:
If the decimal portion of $var1 begins with 08 or 09, it'll have to be massaged.
hi all, i have the following problem using awk in a script
i want to read the values from a column with real numbers and calculate the mean.the problem is that when i use a statement such as this
num = $4
i cant find a way to convert the variable from string to floating point to perform... (7 Replies)
Hai,
Can you please guide me, to compare the floating point numbers.
Eg.
If
then
echo "value1 is grater "
fi
This code is not working properly when i excuted with floating values or real numbers (13 Replies)
Hi,
I am compiling "HelloWorld" C progam on 32-bit CentOS and i want to execute it on 64-bit CentOS architecture.
For that i copied the a.out file from 32-bit to 64-bit machine, but while executing a.out file on 64bit machine I am getting "Floating point exception error".
But we can run... (3 Replies)
Hi All,
I'm trying to extract some floating point numbers from within some HTML code like this:
<TR><TD class='awrc'>Parse CPU to Parse Elapsd %:</TD><TD ALIGN='right' class='awrc'> 64.50</TD><TD class='awrc'>% Non-Parse CPU:</TD><TD ALIGN='right' class='awrc'> ... (2 Replies)
Hi guys
I have problem with my simple calculator, author of my book wrote
One way I tried is to test if one the inpur number is grater than zero, and then substatct
And my protptype function is
#include <stdio.h>
int main(void) {
float a, b , result;
... (11 Replies)
Anyone help me i cant found the error of floating point
if needed, i added the code complete
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
typedef struct
{
int hh;
int mm;
int ss;
char nom;
int punt;
}cancion;
typedef struct... (9 Replies)
I have started using bash but this script which I am working on it, is in c chell. So here is my simple problem:
set x = 0.4124\0.234
echo $x
0.4124.0.234
Same operation in Bash gives me correct result in my terminal. So there is something with my c shell that is causing this behaviour.... (8 Replies)
I have the following code snippet in bash
if ]; then
minm=`echo "$diff" | bc`
fi
It works well for most of the cases. However lets say diff is -0.17 and minm is -0.0017. In such a case the comparison seems to fail. Is the correct way to compare a mixture of positive and... (12 Replies)
Discussion started by: ngabrani
12 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)