Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: regular expression foreign language
Top Forums Shell Programming and Scripting regular expression foreign language Post 302362798 by fpmurphy on Saturday 17th of October 2009 05:59:50 PM
Old 10-17-2009
What you are discusiing is called a collating sequence. Do a web search for "POSIX collating sequence" for further information.

To be language-neutral, your example would be written as
Code:
grep "[[:alpha:]][[:alpha:]]*"  filename

or if you only want lowercase characters
Code:
grep "[[:lower:]][[:lower:]]*"  filename

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Regular Expression + Aritmetical Expression

Is it possible to combine a regular expression with a aritmetical expression? For example, taking a 8-numbers caracter sequece and casting each output of a grep, comparing to a constant. THX! (2 Replies)
Discussion started by: Z0mby
2 Replies

2. Linux

Regular expression to extract "y" from "abc/x.y.z" .... i need regular expression

Regular expression to extract "y" from "abc/x.y.z" (2 Replies)
Discussion started by: rag84dec
2 Replies

3. Shell Programming and Scripting

Regular Expression

Hi, In Perl What should be the regular expression for 1-23. I tried with |1|2. But it is not working. I have a code snippet like below $state = 0; while( $state != 1 ) { $hour=<STDIN>; if ( $hour =~ /|1|2/) { print "Integer within range.\n"; $state = 1;... (3 Replies)
Discussion started by: siba.s.nayak
3 Replies

4. UNIX for Dummies Questions & Answers

ls with regular expression

I currently list and sort all the files in a directory which begin with an Upper Case C and end with the extension '#finished#'. Here is the command I use: ls -tr $currentDir/*.#finished# what i need to do now is list all the files in a directory that begin with upper case C and end... (3 Replies)
Discussion started by: rkgudde
3 Replies

5. Shell Programming and Scripting

Integer expression expected: with regular expression

CA_RELEASE has a value of 6. I need to check if that this is a numeric value. if not error. source $CA_VERSION_DATA if * ] then echo "CA_RELESE $CA_RELEASE is invalid" exit -1 fi + source /etc/ncgl/ca_version_data ++ CA_PRODUCT_ID=samxts ++ CA_RELEASE=6 ++ CA_WEEK_NO=7 ++... (3 Replies)
Discussion started by: ketkee1985
3 Replies

6. Shell Programming and Scripting

Day of the week or Month in a foreign language

Hey guys, i'm a very new shell script user. I've been looking everywhere for a proper script to display the day of the week or the month, accurately, in a foreign language of my choosing. Something where i can just type in the appropriate word in a foreign language in the script and get the... (2 Replies)
Discussion started by: ibizagreg
2 Replies

7. Programming

Perl: How to read from a file, do regular expression and then replace the found regular expression

Hi all, How am I read a file, find the match regular expression and overwrite to the same files. open DESTINATION_FILE, "<tmptravl.dat" or die "tmptravl.dat"; open NEW_DESTINATION_FILE, ">new_tmptravl.dat" or die "new_tmptravl.dat"; while (<DESTINATION_FILE>) { # print... (1 Reply)
Discussion started by: jessy83
1 Replies

8. Shell Programming and Scripting

regular expression and ls

hello using KSH shell i have those files in a folder FILE01 FILE1 FILE02 FILE2 FILE001 FILE0001 in a script i would like to list all the files through regular expressions i tried this ls FILE+* but i receive this error ls: 0653-341 The file FILE+* does not exist. what is... (2 Replies)
Discussion started by: ade05fr
2 Replies

9. UNIX for Advanced & Expert Users

sed: -e expression #1, char 0: no previous regular expression

Hello All, I'm trying to extract the lines between two consecutive elements of an array from a file. My array looks like: problem_arr=(PRS111 PRS213 PRS234) j=0 while } ] do k=`expr $j + 1` sed -n "/${problem_arr}/,/${problem_arr}/p" problemid.txt ---some operation goes... (11 Replies)
Discussion started by: InduInduIndu
11 Replies

10. UNIX for Dummies Questions & Answers

Regular expression help

Hi, I am quite knew to scripting and I am trying to get a regular expression to work to check that a user enters a valid version number such as 1 or 1.1 or 12.3 etc. I dont seem to be able to get it to work as it picks up versions such as 1.......2. I only want it to work with a single dot.... (12 Replies)
Discussion started by: frodo61
12 Replies

LEARN ABOUT OPENSOLARIS

look

look(1) 							   User Commands							   look(1)

NAME

       look - find words in the system dictionary or lines in a sorted list

SYNOPSIS

       /usr/bin/look [-d] [-f] [-tc] string [filename]

DESCRIPTION

       The look command consults a sorted filename and prints all lines that begin with string.

       If no  filename is specified, look uses /usr/share/lib/dict/words with collating sequence -df.

       look limits the length of a word to search for to 256 characters.

OPTIONS

       -d     Dictionary order. Only letters, digits,  TAB and SPACE characters are used in comparisons.

       -f     Fold case. Upper case letters are not distinguished from lower case in comparisons.

       -tc    Set termination character. All characters to the right of c in  string are ignored.

FILES

       /usr/share/lib/dict/words    spelling list

ATTRIBUTES

       See attributes(5) for descriptions of the following attributes:

       +-----------------------------+-----------------------------+
       |      ATTRIBUTE TYPE	     |	    ATTRIBUTE VALUE	   |
       +-----------------------------+-----------------------------+
       |Availability		     |SUNWesu			   |
       +-----------------------------+-----------------------------+

SEE ALSO

       grep(1), sort(1), attributes(5)

SunOS 5.11							    29 Mar 1994 							   look(1)
All times are GMT -4. The time now is 02:26 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy