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Top Forums Programming How i can read a long integer from standar input and a string with as many characters as specified.. Post 302362257 by julianjensen on Thursday 15th of October 2009 11:49:40 AM
Old 10-15-2009
Code:
#include <stdlib.h>
#include <stdio.h>

int main( int argc, char **argv )
{
    int    num;
    char    format[ 8 ];
    char    inps[ 100 ];

    scanf( "%d ", &num );
    sprintf( format, "%%%ds", num );
    scanf( format, inps );
    printf( "format: '%s' -- num: %d, text: %s\n", format, num, inps );
    return( 0 );
}

 

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a64l(3C)																  a64l(3C)

NAME
a64l(), l64a() - convert between long integer and base-64 ASCII string SYNOPSIS
Obsolescent Interface DESCRIPTION
These functions are used to maintain numbers stored in base-64 ASCII characters. This is a notation by which long integers can be repre- sented by up to six characters; each character represents a "digit" in a radix-64 notation. The characters used to represent "digits" are for 0, for 1, through for 2-11, through for 12-37, and through for 38-63. The leftmost character is the least significant digit. For example, a0 = (38 x 64^0) + (2 x 64^1) = 166 takes a pointer to a null-terminated base-64 representation and returns a corresponding value. If the string pointed to by s contains more than six characters, uses the first six. takes a argument and returns a pointer to the corresponding base-64 representation. If the argument is 0, returns a pointer to a null string. Obsolescent Interface converts between long integer and base-64 ASCII string. WARNINGS
The value returned by is a pointer into a buffer, the contents of which are overwritten subsequent calls by the same thread. is an obsolescent interface supported only for compatibility with existing DCE applications. New multithreaded applications should use SEE ALSO
thread_safety(5). STANDARDS CONFORMANCE
a64l(3C)
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