10-15-2009
Hello, I apologize if the message was unclear.
The problem is: I want to use the following advanced regular expression syntax "(?:)" which represents grouping without backreference.
Related information: From what I read GNU Grep supports the advanced syntax.
Support: I've used "()" which is grouping with backreference.
My goal isn't to solve any particular problem really. I'm new to the unix enviroment and right now I'm trying to learn as much about grep and regular expressions as possible. I understand that the advanced syntax with grep is likely going to be academic only since I would find piping into other programs simpler (sed/awk).
Summary: Can I use the syntax "(?:)" with GNU Grep 2.5.1?
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GREP(1) General Commands Manual GREP(1)
NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS
-e -e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)