It's a lot of find runs depending on how many files you are searching for. To make it a bit more efficient I would go with something like this for example:
#!/bin/ksh
for files in `ls *.gz`
do
gunzip -c $files | awk -v s=$files -F\" '{print s","$6}'
done
I have tried FILENAME parameter but it did not work please help. (1 Reply)
using OS X and the Terminal, I'd like to find all locked files in a specified directory, unlock them, and print a list of those files that were unlocked
how can I do this?
I'm familiar with chflags nouchg for unlocking one file but not familiar with unix enough to do what I'd like.
Thanks! (0 Replies)
cat a | awk -F";" '{print "update db set column=' "$2" ' where column1=\""$1"\";"}' > ip-add.sql
Hi! I'm a new user!
i need to use single quote in the double quotes print string
The apex between che "$2" should not be interpreted, but....how?!
I'm trying to use \ but don't work correctly!
... (4 Replies)
Hi, I am new to this unix world.
Any ways, I would like to write a shell script that can print the file name.
Ex :
directory will have 5 files with different name.No matter what are contents are.
Now I need to find the file which will have particular name (sub string ).Please do not... (5 Replies)
I can got the filename with this script. it's only show "-" in result.
cut -d , -f7 CSV_d.* | awk 'OFS=":"{print FILENAME,substr($1,1,8),substr($1,9,2),substr($1,11,2),substr($1,13,2)}' | sort |uniq (2 Replies)
hi,
i have a directory at /path/unix with the following files
1.txt
2.txt
3.txt
4.txt
I want to make another file called filenames.txt at a different location called /path/home. So, my output file would be
/path/home/filenames.txt with contents
/path/unix/1.txt... (1 Reply)
I have files named with different prefixes. From each I want to extract the first line containing a specific string, and then print that line along with the prefix.
I've tried to do this with a while loop, but instead of printing the prefix I print the first line of the file twice.
Files:... (3 Replies)
Hi
I have a requirement like this:
/abc/a/x.txt
/abc/a/y.txt
/abc/b/x.gz
/abc/b/y.txt
I need output like this:
/abc/a:*.txt
/abc/b:*.txt
/abc/b:*.gz
I have tried find /abc -type f -name "*.*" ||awk -F . '{print $NF}' it is print only extensions without path name.
Please... (5 Replies)
The file f1 contains the text "body" (shell prompt is "$"):
$ cat ~/path/f1
body
How to print contents of f1 when the f1 path is in a variable?
Here is my failed attempt:
$ f1="~/path/f1"
$ echo $f1
~/path/f1
$ cat $f1
cat: '~/path/f1': No such file or directory (2 Replies)
Discussion started by: wolfv
2 Replies
LEARN ABOUT X11R4
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)