It's a lot of find runs depending on how many files you are searching for. To make it a bit more efficient I would go with something like this for example:
#!/bin/ksh
for files in `ls *.gz`
do
gunzip -c $files | awk -v s=$files -F\" '{print s","$6}'
done
I have tried FILENAME parameter but it did not work please help. (1 Reply)
using OS X and the Terminal, I'd like to find all locked files in a specified directory, unlock them, and print a list of those files that were unlocked
how can I do this?
I'm familiar with chflags nouchg for unlocking one file but not familiar with unix enough to do what I'd like.
Thanks! (0 Replies)
cat a | awk -F";" '{print "update db set column=' "$2" ' where column1=\""$1"\";"}' > ip-add.sql
Hi! I'm a new user!
i need to use single quote in the double quotes print string
The apex between che "$2" should not be interpreted, but....how?!
I'm trying to use \ but don't work correctly!
... (4 Replies)
Hi, I am new to this unix world.
Any ways, I would like to write a shell script that can print the file name.
Ex :
directory will have 5 files with different name.No matter what are contents are.
Now I need to find the file which will have particular name (sub string ).Please do not... (5 Replies)
I can got the filename with this script. it's only show "-" in result.
cut -d , -f7 CSV_d.* | awk 'OFS=":"{print FILENAME,substr($1,1,8),substr($1,9,2),substr($1,11,2),substr($1,13,2)}' | sort |uniq (2 Replies)
hi,
i have a directory at /path/unix with the following files
1.txt
2.txt
3.txt
4.txt
I want to make another file called filenames.txt at a different location called /path/home. So, my output file would be
/path/home/filenames.txt with contents
/path/unix/1.txt... (1 Reply)
I have files named with different prefixes. From each I want to extract the first line containing a specific string, and then print that line along with the prefix.
I've tried to do this with a while loop, but instead of printing the prefix I print the first line of the file twice.
Files:... (3 Replies)
Hi
I have a requirement like this:
/abc/a/x.txt
/abc/a/y.txt
/abc/b/x.gz
/abc/b/y.txt
I need output like this:
/abc/a:*.txt
/abc/b:*.txt
/abc/b:*.gz
I have tried find /abc -type f -name "*.*" ||awk -F . '{print $NF}' it is print only extensions without path name.
Please... (5 Replies)
The file f1 contains the text "body" (shell prompt is "$"):
$ cat ~/path/f1
body
How to print contents of f1 when the f1 path is in a variable?
Here is my failed attempt:
$ f1="~/path/f1"
$ echo $f1
~/path/f1
$ cat $f1
cat: '~/path/f1': No such file or directory (2 Replies)