hi i am trying to get digits inside brackes from file , whose structure is defined below
CREATE TABLE TELM
(SOC_NO CHAR (3) NOT NULL,
TXN_AMOUNT NUMBER (17,3)
SIGN_ON_TIME CHAR (8)
TELLER_APP_LIMIT NUMBER (17,3)
FIL01 ... (2 Replies)
Hello,
I have a comma delimited input feed file. The first field has directory location and the second field has file name.
Ex of input feed:
/export/appl/a,abc*.dat
/export/appl/b,xyz*.dat
/export/appl/c,pmn*.dat
Under each directory, there would be many files like...
.
.
.... (4 Replies)
I would like to find a list of files in a directory less than 2 days old and put them into an array variable. And then search for each file in the array for a matching string say "Return-code= 0". If it matches, then display the array element with a message as "OK".
Your help will be greatly... (1 Reply)
I am trying to use a script to replace the header of each file, whose filename are stored within the array $test, using the sed command within a Perl script as follows:
$count = 0;
while ( $count < $#test )
{
`sed -e 's/BIOGRF 321/BIOGRF 332/g' ${test} > 0`;
`cat 0 >... (2 Replies)
Hi Everyone,
I have:
my @No=qw(032106 032630 0380 034010 035110 0354801111);
my $str_No=join(';', @No);
I have a string $strA="03263033", so in order to determine this $strA area code matches with @No, I can do:
if ( (rindex($str_No,substr($strA,0,5))))== -1) ) {
print "Not... (1 Reply)
Hello experts,
I have a file containing the following text(shortened here).
File Begin
----------
< # Billboard.d3fc1302a677.imagePath=S:\\efcm_T4
< Billboard.d3fc1302a677.imagePath=S:\\efcm_T4
---
> # Billboard.d3fc1302a677.imagePath=S:\\efcm_Cassini
>... (2 Replies)
Hello,
I have the following perl array:
@longname = (Fasthernet0/0 Fasthernet0/1 Serial0/1/0 Serial0/2/1 Tunnel55 Tunnel77)
with the followinh array:
@shortname = (Fa0/0 Fa0/1 Se0/1/0 Se0/2/1 Tu55 Tu77)
in other words, I need to remove the following from each element in the array... (4 Replies)
Hi,
I have two files like this
file 1:
xxtcgtatccgaggga
cgcgcgggggagg
jjsjjjjsjjjdtcgtat
aaaaaaacccaaan
ggtcgtatffaadda
gggctggalllslllssdkk
file 2:
tcgtat
gctggaI want to 1) match each element of file2 to each element of file1.
2) delete all the matched alphabets and subsequent... (3 Replies)
I have an array and two variables as below,
I need to check if $datevar is present in $filename.
If so, i need to replace $filename with the values in the array.
I need the output inside an ARRAY
How can this be done.
Any help will be appreciated. Thanks in advance. (2 Replies)
Experts,
I am looking to compare elements of 2 array using perl. Below is not the actual code but logic wise something like this.
my $version = "MYSQlcl-5.2.4-264.x86_64"; <-- split this word into array as (5 2 4 264) ( which is to extract only the version number from the package name)
my... (1 Reply)
Discussion started by: solaix14
1 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)