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Top Forums Shell Programming and Scripting ...yet another string of awk/sed questions from a RegExp-Challenged luser %-\ Post 302358528 by Scrutinizer on Friday 2nd of October 2009 09:59:07 PM
Old 10-02-2009
The problem is with the ;& body termination, which is used for "falling through" in case statements. I guess this is a Kornshell-only feature.

I have adjusted the code somewhat so that it works in both ksh and bash:
Code:
#!/bin/ksh
# First Step 2
mergedline=0
{ sed 's/^\([CDS]\) \(.*\)$/\2 \1/' infile |\
while read line; do
  case $line in
      # Step 3
      \[*) printf "$prevline $line\n"
           mergedline=1
           prevline="" ;;
      # Step 4
      *)   if [[ $mergedline -eq 0 ]]; then
             echo $prevline
      # Step 1
             case $line in
               *subnets*|*masks*) echo ;;
             esac
           fi
           mergedline=0
           prevline=$line  ;;
  esac;
done;
if [[ $mergedline -eq 1 ]]; then
  echo $prevline
fi } | \
while read firstline; do  # Step 5
  while read line; do
    if [[ $firstline != "" ]]; then
      echo $firstline
      firstline=""
    fi
    if [[ $line != "" ]]; then
      echo $line
    else
      break
    fi
  done|sort -n -t. -k1,1 -k2,2 -k3,3 -k4,4
  echo
done
if [[ $firstline != "" ]]; then
  echo $firstline
fi



---------- Post updated at 05:59 PM ---------- Previous update was at 05:36 PM ----------

And this version works in sh/dash too:

Code:
#!/bin/sh
# First Step 2
mergedline=0
{ sed 's/^\([CDS]\) \(.*\)$/\2 \1/' infile |\
while read line; do
  case $line in
      # Step 3
      \[*) printf "$prevline $line\n"
           mergedline=1
           prevline="" ;;
      # Step 4
      *)   if [ $mergedline -eq 0 ]; then
             echo $prevline
      # Step 1
             case $line in
               *subnets*|*masks*) echo ;;
             esac
           fi
           mergedline=0
           prevline=$line  ;;
  esac;
done;
if [ $mergedline -eq 1 ]; then
  echo $prevline
fi } | \
while read firstline; do  # Step 5
  while read line; do
    if [ -n "$firstline" ]; then
      echo $firstline
      firstline=""
    fi
    if [ -n "$line" ]; then
      echo $line
    else
      break
    fi
  done|sort -n -t. -k1,1 -k2,2 -k3,3 -k4,4
  echo
done
if [ -n "$firstline" ]; then
  echo $firstline
fi

 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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