How to get the exit code of -exec in the find command
Hi
I have a little problem with the find command in a script that I'm writing. The script should check if there are some files younger than 100 seconds and then syncronise them with rsync.
My find command:
When I check the exit code with $? I always get 0 even if I can be sure the rsync should fail. How can I get the exit code of the rsync and the find?
I allready contacted the man page but it didn't really helped me much.
Quote:
Find man page:
Execute command; true if 0 status is returned.
Last edited by Neo; 09-29-2009 at 05:10 AM..
Reason: code tags for commands, please.
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Please could someone help with the following command requirement.
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rm syst1202.file ?
etc
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i feel weird with this 2 command
find /tmp/*test* -user `whoami` -mtime +1 -type f -exec rm -f {}\;
find /tmp/*test* -user `whoami` -mtime +1 -type f -exec ls -lrt {}\;
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Hi all,
I am trying to find files newer than a given file and them mv them to a new location.
So I far I have:
find . ! -newer <file_name> -exec ls -l {} \;
and
find . ! -newer <file_name> -exec mv /TEMP_LOCATION {} \;
find is not liking this.
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Hello.
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