I can't open my index.php page after insert php code Post: 302355162

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Top Forums Web Development I can't open my index.php page after insert php code Post 302355162 by metalfreakbr on Monday 21st of September 2009 08:17:28 PM

09-21-2009

Registered User

I can't open my index.php page after insert php code

Hello guys,
Does anyone can help me?
I've just made my simple index.php without any code, but after insert session code to check if any user is authenticated, my index.php doesn't work anymore.
Any fresh eyes could help me to see what and where the code is wrong?

Code:

<?
                    if ($_POST['entrar']=='Entrar!')
                       {
                        @session_start();
                        $result = mysql_query('select log_nome,senha from usuarios where log_nome="'.trim($nome).'";',$conexao);
                        if (mysql_num_rows($result)>0)
                        {
                         $usuSenha = mysql_result($result,0,senha);
                        else
                        {
                         $usuSenha = 'notuser';
                        }
                         if ($result and ($senha==$usuSenha) and ($usuSenha<>'notuser'))
                         {
                          @session_register($nome);
                          echo '<p align="center">';
                          echo '<font style="Tahoma" size=4>';
                          echo $nome.'</font><BR>';
                          echo '<font style="Tahoma" size=2>';
                          echo 'Voc� est� on-line</font>';
                          echo '</p>';
                         }
                         else
                         {
                          echo 'Usu�rio n�o autorizado';
                         }
                        }
                        else
                        {
                         echo '<form method="post" name="logar" action="">
                         <font style="Tahoma" size=1>
                               Nome: <input type="text" name="nome" value="" size="15"><BR>
                               Senha: <input type="text" name="senha" value="" size="15"><BR>
                         </font>
                         <p align="center">
                         <input onmouseover=this.style.cursor="hand" type="submit"
                         name="entrar" value="Entrar!" STYLE="border:0; height:18;
                         width=50; background:#E8F3FD">
                         </p>
                               </form>';
                        }
                    ?>

I'll apreciate any kind of help.
Thanks

metalfreakbr

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LEARN ABOUT PHP

http_response_code

HTTP_RESPONSE_CODE(3)							 1						     HTTP_RESPONSE_CODE(3)

http_response_code - Get or Set the HTTP response code

SYNOPSIS

       int http_response_code ([int  $response_code])

DESCRIPTION

	If you pass no parameters then http_response_code will get the current status code. If you pass a parameter it will set the response code.

PARAMETERS

	      o $response_code
		- The optional $response_code will set the response code.

	      <?php
	      http_response_code(404);
	      ?>

RETURN VALUES

	The current response code. By default the return value is int(200).

EXAMPLES

       Example #1

	      Examples using http_response_code(3)

	      <?php

	      // Get the current default response code
	      var_dump(http_response_code()); // int(200)

	      // Set our response code
	      http_response_code(404);

	      // Get our new response code
	      var_dump(http_response_code()); // int(404)
	      ?>

	      The above example will output:

SEE ALSO

       header(3), headers_list(3).

PHP Documentation Group 												     HTTP_RESPONSE_CODE(3)