sed problem - delete all lines until a match on 2 lines
First of all, I know this can be more eassily done with perl or other scripting languages but, that's not the issue. I need this in sed. (or wander if it's possible )
I got a file (trace file to recreate the control file from oracle for the dba boys)
which contains
Code:
some lines
another line
...
STARTUP NOMOUNT
some lines
another line
...
a line ending with ;
STARTUP NOMOUNT
some lines
another line
...
a line ending with ;
The file contains also some lines in comment in between the others. These lines start with '#'
I want the part from the first "STARTUP NOMOUNT" untill the line before the second "STARTUP NOMOUNT" in 1 file and the part from the second "STARTUP NOMOUNT" untill the end in another file.
I know how to do this in ksh and I guess I would quickly find a solution in perl also but, now it's time to sharpen my sed skills
I already gor this
Code:
sed '/^STARTUP NOMOUNT/,/^STARTUP NOMOUNT/!d' ikke | sed '/^#/d' | sed '$d'
This will delete all the lines except those between the 2 occurences on "STARTUP NOMOUNT", next it will delete the lines in comment and finally it will delete the last line which is the second occurence of "STARTUP NOMOUNT". So, this gives me already 1 file with the first part.
But, how do I get the second part ?
I already tried
Code:
sed '/^STARTUP NOMOUNT/,$!d' ikke | sed '/^#/d' | sed '1,/^STARTUP NOMOUNT/d'
On Unix, it is easy to get those lines that match a pattern, by
grep pattern file
or those lines that do not, by
grep -v pattern file
but I am editing a file on Windows with Ultraedit.
Ultraedit support regular expression based search and replace.
I can delete all the lines that match a... (1 Reply)
Hi all,
I have the following data in a file x.csv:
> ,this is some text here
> ,,,,,,,,,,,,,,,,2006/11/16,0.23
> ,,,,,,,,,,,,,,,,2006/12/16,0.88
< ,,,,,,,,,,,,,,,,this shouldnt be deleted
I need to use SED to match anything with a > in the line and delete that line, can someone help... (7 Replies)
I have this input file that I need to remove lines which represents more than 30 days of processing.
Input file:
On 11/17/2009 at 12:30:00, Program started processing...argc=7
Total number of bytes in file being processed is 390
Message buffer of length=390 was allocated successfully... (1 Reply)
i need to delete the lines is match from file data 1 & data 2
please help?
data 1
4825307
4825308
4825248
4825309
4825310
4825311
4825336
data 2
4825248 0100362210 Time4Meal 39.00 41.73 MO & MT MT SMS
4825305 0100367565... (2 Replies)
Hello,
I'm trying to figure out how to use sed or awk to delete single lines in a file. By single, I mean lines that are not touching any other lines (just one line with white space above and below).
Example:
one
two
three
four
five
six
seven
eight
I want it to look like: (6 Replies)
Hi
Im trying to do the following in sed. I want to delete any blank line at the start of a file until it matches a pattern and then stops. for example:
Input
output:
I have got it to work within a range of two patterns with the following:
sed '/1/,/pattern/{/^]*$/d}'
The... (2 Replies)
Hello,
Could someone help me with sed. I have searched for solution 5 days allready :wall:, but cant find. Unfortunately my "sed" knowledge not good enough to manage it. I have the text:
123, foo1, bar1, short text1, dat1e, stable_pattern
124, foo2, bar2, long text
with few
lines, date,... (4 Replies)
I want to do something like sed -n '/PATTERN/,+10p' and get the ten lines following PATTERN. However, this throws an "expected context address" with the sed that comes with OSX Lion. If that + is a GNUism, can I do this, or do I have to find another tool? (2 Replies)
BASH in Solaris 10
I have a log file like below. Whenever the pattern ORA-39083 is encountered, I want to delete the line which has this pattern and 3 lines below it.
$ cat someLogfile.txt
ORA-39083: Object type OBJECT_GRANT failed to create with error:
ORA-01917: user or role 'CMPA' does... (4 Replies)
Discussion started by: kraljic
4 Replies
LEARN ABOUT MINIX
grep
GREP(1) General Commands Manual GREP(1)NAME
grep - search a file for lines containing a given pattern
SYNOPSIS
grep [-elnsv] pattern [file] ...
OPTIONS -e-e pattern is the same as pattern
-c Print a count of lines matched
-i Ignore case
-l Print file names, no lines
-n Print line numbers
-s Status only, no printed output
-v Select lines that do not match
EXAMPLES
grep mouse file # Find lines in file containing mouse
grep [0-9] file # Print lines containing a digit
DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions
accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1
occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a
match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is
returned.
SEE ALSO cgrep(1), fgrep(1), sed(1), awk(9).
GREP(1)
09-17-2009
sed problem - delete all lines until a match on 2 lines
