09-16-2009
\r in bash script
I'm having some problem with a bash script. Actually what I want to do is compress different files with some mask that includes the date.
Here's my script
#korn
date=`date '+%Y%m%d'`
echo $date
path="tar -cf /cdr_files/cdr_backups/${date}_ADJT.tar"
echo $path
What I want as an output is: tar -cf /cdr_files/cdr_backups/20090916_ADJT.tar and I'm getting something different.
Here's the output that I'm getting excecuting the bash -x
++ date +%Y%m%d
+ date=$'20090916\r'
+ echo $'20090916\r\r'
20090916
'ADJT.tarar -cf /cdr_files/cdr_backups/20090916
+ echo tar -cf $'/cdr_files/cdr_backups/20090916\r_ADJT.tar\r\r'
_ADJT.tarcdr_files/cdr_backups/20090916
Are the \r the problems? How can I remove them?
Thanks in advanced
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LEARN ABOUT PHP
datetimeinterface.format
DATETIMEINTERFACE.FORMAT(3) 1 DATETIMEINTERFACE.FORMAT(3)
DateTime::format - Returns date formatted according to given format
Object oriented style
SYNOPSIS
public string DateTime::format (string $format)
DESCRIPTION
string DateTimeImmutable::format (string $format) string DateTimeInterface::format (string $format)
Procedural style
string date_format (DateTimeInterface $object, string $format)
Returns date formatted according to given format.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3)
o $format
- Format accepted by date(3).
RETURN VALUES
Returns the formatted date string on success or FALSE on failure.
EXAMPLES
Example #1
DateTimeInterface.format(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
echo $date->format('Y-m-d H:i:s');
?>
Procedural style
<?php
$date = date_create('2000-01-01');
echo date_format($date, 'Y-m-d H:i:s');
?>
The above example will output:
2000-01-01 00:00:00
NOTES
This method does not use locales. All output is in English.
SEE ALSO
date(3).
PHP Documentation Group DATETIMEINTERFACE.FORMAT(3)