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Top Forums Shell Programming and Scripting Using Seq As A Variable With Padded Digits Post 302353316 by Grizzly on Tuesday 15th of September 2009 05:54:52 AM
Old 09-15-2009
Using Seq As A Variable With Padded Digits

Hi all. Im trying to use a sequence in a while loop like this below. I need it for navigating a year, month, day folder structure where a user can input the start date and have it go to the desired end date. The script will grab a certain file on each day then move onto the next. Ive got all that worked out using a static set of years in a for loop rather then a while loop with a seq. The problem is when I run into the month andn day folders as they are 01 02 03..10 11. Using the + 1 method it wont cd to the folders below 10 because the var is 1 2 3 instead of 01 02 03. Is there a way to make it add the zero to values below 10 but still keep count?



Code:
startdate=1
enddate=12
a=$startdate
if [ $a -lt 10 ]
   then a=0$a
   fi
 
while [ $a -lt $enddate ]
   DO OTHER THINGS HERE
   startdate=`expr $startdate + 1`
   a=$startdate
if [ $a -lt 10 ]
   then a=0$a
   fi
   done

 

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GREGORIANTOJD(3)							 1							  GREGORIANTOJD(3)

gregoriantojd - Converts a Gregorian date to Julian Day Count

SYNOPSIS
int gregoriantojd (int $month, int $day, int $year) DESCRIPTION
Valid Range for Gregorian Calendar 4714 B.C. to 9999 A.D. Although this function can handle dates all the way back to 4714 B.C., such use may not be meaningful. The Gregorian calendar was not instituted until October 15, 1582 (or October 5, 1582 in the Julian calendar). Some countries did not accept it until much later. For exam- ple, Britain converted in 1752, The USSR in 1918 and Greece in 1923. Most European countries used the Julian calendar prior to the Grego- rian. PARAMETERS
o $month - The month as a number from 1 (for January) to 12 (for December) o $day - The day as a number from 1 to 31 o $year - The year as a number between -4714 and 9999 RETURN VALUES
The julian day for the given gregorian date as an integer. EXAMPLES
Example #1 Calendar functions <?php $jd = GregorianToJD(10, 11, 1970); echo "$jd "; $gregorian = JDToGregorian($jd); echo "$gregorian "; ?> SEE ALSO
jdtogregorian(3), cal_to_jd(3). PHP Documentation Group GREGORIANTOJD(3)
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