Hi,
I need ur help is this matter, i have th ebelow script, and i keep getting this error: syntax error: unexpected end of file
affectedRow=`cat dbOutput.log | grep "1 row affected"`
echo "affectedRow : $affectedRow"
if ; then
echo "Look to the next OMCDB"
... (10 Replies)
I have a script that's failing
./zzmaster.sh: line 2: syntax error: unexpected end of file
There are 4 scripts total involved. The first 'znocc0.sh' essentially curls a page then does some sed sequences...
#!/bin/sh
#GET SENTINAL INFO
curl -b z0cookie.txt -L -k -e... (2 Replies)
Hi,
I am newbie to UNIX scripting. I am facing this error "syntax error: unexpected end of file" while executing the following script:
------
a=$1
if
then
sqlplus -s prospect_stg/prospect_stg@mdmpt <<END
insert into bckup_marc_parameter_lookup select * from... (6 Replies)
I will appreciate help is this matter. i am getting this error (./getwind.scr: line 41: syntax error: unexpected end of file) in the following script :
##############################
#QSUB -eo -q sb -lT 1200 -s /bin/csh
#Run on an HP-UX machine or norway to access ncks
# lat and lon are in... (0 Replies)
Hi all,
I am very new to programming and even newer to this forum as well, so I apologize if this should have been in the Newbie category, but...
I am currently trying to figure out Shell Scripting and am running into problems early. Not having taken any kind of programming class, I am not even... (2 Replies)
I am new to unix, so thank u for ur patience
I try to make it work (to duplicate two first columns in several files):
#!/bin/bash
for i in `seq 2 5`
do
awk `{ print $1,$1,$2,$2,$3,$4}` final_chr.${i} > input_${i}
done
and i get
./my_script3.sh: command substitution: line 5: syntax... (2 Replies)
Hi,
I am getting error while running the script. "syntax error: unexpected end of file"
if i do cat i cant see the content of the script also it is showing as
cat test.sh
doner /home/master/* /home/Priya/$i| while read i j
The original script is
paste /home/names.txt /home/ip.txt |... (6 Replies)
I checked the forum and internet, tried different workaorunds but it didnt fixed the error.
Please advise on the code.
#!/bin/sh
CWD=/home/test/Bench
cd $CWD
(grep "`date +%d-%b"`" File.txt) > /home/test/Bench/dateout
if
then
echo “data” > /home/test/ Bench /test
else
echo "File... (16 Replies)
Hi,
I am brand new to this so I apologize ahead of time for any formatting problems.
I know there is a previous (closed) thread on here about this problem but I wasn't able to fix the error following the posts there so I thought I could create a new one.
Here is the error I am getting:
... (3 Replies)
Discussion started by: SierraG
3 Replies
LEARN ABOUT PHP
forward_static_call_array
FORWARD_STATIC_CALL_ARRAY(3) 1 FORWARD_STATIC_CALL_ARRAY(3)forward_static_call_array - Call a static method and pass the arguments as arraySYNOPSIS
mixed forward_static_call_array (callable $function, array $parameters)
DESCRIPTION
Calls a user defined function or method given by the $function parameter. This function must be called within a method context, it can't
be used outside a class. It uses the late static binding. All arguments of the forwarded method are passed as values, and as an array, sim-
ilarly to call_user_func_array(3).
PARAMETERS
o $function
- The function or method to be called. This parameter may be an array, with the name of the class, and the method, or a string,
with a function name.
o $parameter
- One parameter, gathering all the method parameter in one array.
Note
Note that the parameters for forward_static_call_array(3) are not passed by reference.
RETURN VALUES
Returns the function result, or FALSE on error.
EXAMPLES
Example #1
forward_static_call_array(3) example
<?php
class A
{
const NAME = 'A';
public static function test() {
$args = func_get_args();
echo static::NAME, " ".join(',', $args)."
";
}
}
class B extends A
{
const NAME = 'B';
public static function test() {
echo self::NAME, "
";
forward_static_call_array(array('A', 'test'), array('more', 'args'));
forward_static_call_array( 'test', array('other', 'args'));
}
}
B::test('foo');
function test() {
$args = func_get_args();
echo "C ".join(',', $args)."
";
}
?>
The above example will output:
B
B more,args
C other,args
SEE ALSO forward_static_call(3), call_user_func(3), call_user_func_array(3), is_callable(3), information about the callback type.
PHP Documentation Group FORWARD_STATIC_CALL_ARRAY(3)