Hi ,
I am relatively new to unix...
Can u pls help me out to find out if the first day of the month is a working day ie from (Monday to Friday)...using Date and If clause in Korn shell..
This is very urgent.
Thanks for ur help... (7 Replies)
How to find the first day of previous month in unix mmddyyyy format?
example : today is 07052007 (in mmddyyyy)
output sud be 06012007
thanks
mohapatra (10 Replies)
Hi,
I want a script(ksh) to see if today is the last working day(Mon-Fri) of the month. If it is the last working day I need to print current date, else I need the last working day of previous month. Thanks in advance. (1 Reply)
Hello,
I wanted to display the month for previous day date. Like, today date is 18-Nov-2008. So the previous date is 17-Nov-2008. The output should be November.
If the today date is 1-DEC-2008, then output should be NOVEMBER.
If the today date is 1-JAN-2008, then output should be DECEMBER.... (4 Replies)
Hello - I have one question regarding the date. I wanted to display the month name for previous day. The output should be as follows...
5-Feb-09 => February
1-Feb-09 => January
28-Feb-09=> February
Here is the code i am using to get the output....
date '+%m %d %Y' |
{
read MONTH DAY... (4 Replies)
Hello,
How do I convert unix timestamp value to 'normal' date format - to get year month and day values ?
Looks like it's easy to do using GNU date (linux systems). But how do I do tthis on AIX ?
I don't want to write C program, any ways to do that using unix shells ?
thanks (1 Reply)
Hi,
I would like to write a script that checks if a file ('counter') was modified the previous day, if so erase its contents and write 00000000 into it.
For e.g. if the file 'counter' was last modified at 11.30pm on 24th May and the script runs at 12.15am of 25th May, it should erase it's... (1 Reply)
Hi Guys,
How to get First day of previous month and last day of previous month from trunc(sysdate) using SQL..?
Thanks in advance.
Br,
pinpe (2 Replies)
Hi All,
I have a requirement where I need to first capture the current day & move all the files from a particular directory based on a previous day.
i.e move all the files from one directory to another based on current day & a previous day. Here is what I am trying, but it gives me errors.... (2 Replies)
Hi Experts,
i am using the below code get the date of previous day.
#!/usr/bin/ksh
datestamp=`date '+%Y%m%d'`
yest=$((datestamp -1))
echo $yest
When i execute the code i am getting output as:
20130715
What i am trying here is, based on the date passed i am fetching previus day's... (0 Replies)
Discussion started by: learner24
0 Replies
LEARN ABOUT PHP
datetime.add
DATETIME.ADD(3) 1 DATETIME.ADD(3)DateTime::add - Adds an amount of days, months, years, hours, minutes and seconds to a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::add (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_add (DateTime $object, DateInterval $interval)
Adds the specified DateInterval object to the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.add(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-01');
date_add($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-11
Example #2
Further DateTime.add(3) examples
<?php
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-01');
$date->add(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-01 10:00:30
2007-06-05 04:03:02
Example #3
Beware when adding months
<?php
$date = new DateTime('2000-12-31');
$interval = new DateInterval('P1M');
$date->add($interval);
echo $date->format('Y-m-d') . "
";
$date->add($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-01-31
2001-03-03
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.sub(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.ADD(3)