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Full Discussion: Perl - setting a variable ?
Top Forums Shell Programming and Scripting Perl - setting a variable ? Post 302349473 by rethink on Tuesday 1st of September 2009 05:43:54 AM
Old 09-01-2009
Perl - setting a variable ?

hi there, I have a question about a snippet of code i have which runs localtime() to convert the current date/time into a mysql happy format



Code:
my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime(time);
printf "%4d-%02d-%02d  %02d:%02d:%02d\n",$year+1900,$mon+1,$mday,$hour,$min,$sec;

If i run the above as a standalone script, i get the desired result

Code:
 # ./time.pl 
2009-09-01 10:22:18

However, what i want to do is incorporate it as part of another script and populate an internal variable with the result rather than sending it to standard out ...so i tried this

Code:
my ($sec,$min,$hour,$mday,$mon,$year,$wday,$yday,$isdst)=localtime(time);
my  $datetime = printf "%4d-%02d-%02d  %02d:%02d:%02d\n",$year+1900,$mon+1,$mday,$hour,$min,$sec;

print "\n datetime equals $datetime\n";

Code:
# ./time.pl 
2009-09-01 10:10:31

datetime equals 1
#

but as you can see, not only has it still output to result to standard out (not ideal), but it has populated the variable $datatime with the value "1"

is there something im doing drstically wrong here

any hlp would be great
 

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