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Top Forums Shell Programming and Scripting assigning complicated input to a variable Post 302348786 by sigtor77 on Saturday 29th of August 2009 05:24:33 PM
Old 08-29-2009
assigning complicated input to a variable

I cannot seem to correctly assign this line of code to a variable:

HITS=`pwd`/csv/LightningProbability30minAlignmentErrorTable_*.csv | sed 's/,/ /g' | awk '{print int(100*$5)}' | wc

This does not work.

I tried surrounding it in backticks, but I think the backticks in `pwd` is messing it up.

Any ideas?
 

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PWD(1)							    BSD General Commands Manual 						    PWD(1)

NAME
pwd -- return working directory name SYNOPSIS
pwd [-L | -P] DESCRIPTION
The pwd utility writes the absolute pathname of the current working directory to the standard output. Some shells may provide a builtin pwd command which is similar or identical to this utility. Consult the builtin(1) manual page. The options are as follows: -L Display the logical current working directory. -P Display the physical current working directory (all symbolic links resolved). If no options are specified, the -L option is assumed. ENVIRONMENT
Environment variables used by pwd: PWD Logical current working directory. EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs. SEE ALSO
builtin(1), cd(1), csh(1), sh(1), getcwd(3) STANDARDS
The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1''). BUGS
In csh(1) the command dirs is always faster because it is built into that shell. However, it can give a different answer in the rare case that the current directory or a containing directory was moved after the shell descended into it. The -L option does not work unless the PWD environment variable is exported by the shell. BSD
April 12, 2003 BSD
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