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Top Forums Shell Programming and Scripting Function call with argument doubt Post 302348347 by canishk on Friday 28th of August 2009 03:44:55 AM
Old 08-28-2009
Power

Quote:
Originally Posted by ripat
No, as

is not correct. You can not assign a value to an array that way as the function only returns a code, not a value.
Just do something like this:
Code:
iterate_directory()
{
cd $1
k=0
for i in *
    do
        if [ -d "$i" ]
        then
            array1[k++]=${i}
        fi
    done
}

So there is no use of functions, if there is no means of re-usability then what is the need of functions ?Smilie
 

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ARRAY_DIFF(3)								 1							     ARRAY_DIFF(3)

array_diff - Computes the difference of arrays

SYNOPSIS
array array_diff (array $array1, array $array2, [array $...]) DESCRIPTION
Compares $array1 against one or more other arrays and returns the values in $array1 that are not present in any of the other arrays. PARAMETERS
o $array1 - The array to compare from o $array2 - An array to compare against o $... - More arrays to compare against RETURN VALUES
Returns an array containing all the entries from $array1 that are not present in any of the other arrays. EXAMPLES
Example #1 array_diff(3) example <?php $array1 = array("a" => "green", "red", "blue", "red"); $array2 = array("b" => "green", "yellow", "red"); $result = array_diff($array1, $array2); print_r($result); ?> Multiple occurrences in $array1 are all treated the same way. This will output : Array ( [1] => blue ) NOTES
Note Two elements are considered equal if and only if (string) $elem1 === (string) $elem2. In words: when the string representation is the same. Note This function only checks one dimension of a n-dimensional array. Of course you can check deeper dimensions by using array_diff($array1[0], $array2[0]);. SEE ALSO
array_diff_assoc(3), array_intersect(3), array_intersect_assoc(3). PHP Documentation Group ARRAY_DIFF(3)
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