I have set up a simple awk script to calculate the average of values that are printed out a number of times per second (the number of time the printing occurs varies). The data is of the format shown below:
Where the leftmost column is the second that the data printed out and the rightmost column contains the value. What I would like to do is to for each second, find the average of the values for that second and print out the result, then move on to the next second.
I only started using AWK a day or so again and have been trying to get my head around this. The idea behind the script below is, the sum will be calculated until no more data exists for that second, at which point the average is calculated and printed. The script will then move on to calculate the values for the next second. I have tried everything, but cannot see to get it to work.
hi all. i have a little problem. im basically reading input from the user from the keyboard into the variable "phonenumber". I want to do a little error check to check if the user doesnt enter anything in for the value phonenumber.
i had this:
read phonenumber
if
then
.....
else
........ (2 Replies)
Hi everyone - I am sure this is a really simple problem but I'm a total noob at Linux scripting:
I wanted to create a script that allows me to compare the current week number to the contents of a text file in my home directory:
VAR1='date +%V'
VAR2='cat /home/fred/file.txt'
... (6 Replies)
Hi
New to shell script and awk and need assistance on this problem. I need to use a variable to substitute a string in an external file and write the changed info to another file.
At first I did not know if you could use a variable as the sub value but the following showed me that I can.
... (3 Replies)
Hello;
Trying to figure out how to keep just the contents between the two search lines:
awk '/regexp_1/ ,/regexp_2/'
I do not want lines containing regexp_1 and regexp_2 in the output.
Thank you for any ideas
Video tutorial on how to use code tags in The UNIX and Linux Forums. (5 Replies)
Hello;
I need to print two previous lines after searching for a reg exp:
awk '/haywood/'
should produce the following
===================
p9J46THe020804 89922 Tue Oct 18 21:06 MAILER-DAEMON
(host map: lookup (haywood.com): deferred)
... (1 Reply)
Hello;
we have :
awk '/reg_exp/,0/
prints every line after the first occurrence of "reg_exp"
But if I want to print rest of the lines AFTER the last occurrence of "reg_exp",
how would I do it ??
Tried :
awk ' ! (/reg_exp/,0)'
But it errored...
Thank you for any... (5 Replies)
Discussion started by: delphys
5 Replies
LEARN ABOUT DEBIAN
igawk
IGAWK(1) Utility Commands IGAWK(1)NAME
igawk - gawk with include files
SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ...
igawk [ all gawk options ] [ -- ] program-text file ...
DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1).
AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like
@include getopt.awk
in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path.
OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports.
EXAMPLES
cat << EOF > test.awk
@include getopt.awk
BEGIN {
while (getopt(ARGC, ARGV, "am:q") != -1)
...
}
EOF
igawk -f test.awk
SEE ALSO gawk(1)
Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995.
AUTHOR
Arnold Robbins (arnold@skeeve.com).
Free Software Foundation Nov 3 1999 IGAWK(1)