you can use sed search and replace to just print the match, you just have to put the pattern in parentheses, and then reference the match in the replace part with a \1
the ugly part is that you have to escape the parentheses with backslashes.
There is probably a better way, but this is short, and works like a charm
Hi,
I have file 1.txt with following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433
**
**
**
In file 2.txt I have the following entries as shown:
0152364|134444|10.20.30.40|015236433
0233654|122555|10.20.30.50|023365433... (4 Replies)
Hi all,
I'm looking for some help. I have a file (very long) that is organized like below:
>Cluster 0
0 283nt, >01_FRYJ6ZM12HMXZS... at +/99%
1 279nt, >01_FRYJ6ZM12HN12A... at +/99%
2 281nt, >01_FRYJ6ZM12HM4TS... at +/99%
3 283nt, >01_FRYJ6ZM12HM946... at +/99%
4 279nt,... (4 Replies)
All,
I have the following file:
--------------------------------------
#
# /etc/pam.d/common-password - password-related modules common to all services
#
# This file is included from other service-specific PAM config files,
# and should contain a list of modules that define the services... (2 Replies)
one.txt
ONS.820.log:V 20Oct2010:GP ^ ^
ONS.123.log:V 21Oct2010:GP ^ ^
ONS.820.log:V 30Oct2010:GP ^ ^
want to make new file from existing one with addition.
20Oct2010 User KV001 has name tk003 with buffer- 338-1
21Oct2010 User KV003 has name tk002 with buffer- 338-2
30Oct2010 User KV002... (5 Replies)
I have a file a file having entries are like
@ram@sham@sita
@krishan@kumar
@deep@kumar@hello@sham
in this file all line are having different no of pattern-@.
need to fetch the substring after the last pattern.
like
sita
kumar
sham
thanks in advance (3 Replies)
Hi,
I am trying to get a result out of this but fails please help. Have two files /tmp/1 & /tmp/hosts.
/tmp/1
IP=123.456.789.01
WAS_HOSTNAME=abcdefgh.was.tb.dsdc
/tmp/hosts
123.456.789.01
I want this result in /tmp/hosts if hostname is already there dont want duplicate entry.
... (5 Replies)
'Hi
I'm using the following code to extract the lines(and redirect them to a txt file) after the pattern match. But the output is inclusive of the line with pattern match.
Which option is to be used to exclude the line containing the pattern?
sed -n '/Conn.*User/,$p' > consumers.txt (11 Replies)
The sample file:
dept1: user1,user2,user3
dept2: user4,user5,user6
dept3: user7,user8,user9
I want to match by '/^dept2.*/' but don't want to have substring 'dept2:' in output. How to compose such regex? (8 Replies)
Hi Gurus,
I have a file as follows (Sample shown below but the list is very huge)
SCHEDULE WS1#JS1
RUNCYCLE1
:
WS1#JOB1
WS1#JOB2
FOLLOWS JOB1
END
SCHEDULE WS2#JS1
RUNCYCLE2
:
WS1#JOB3
WS1#JOB1
FOLLOWS JOB3
WS2#JOB1 (10 Replies)
Hi all!
Thanks for taking the time to view this!
I want to grep out all lines of a file that starts with pattern 1 but also does not match with the second pattern.
Example:
Drink a soda
Eat a banana
Eat multiple bananas
Drink an apple juice
Eat an apple
Eat multiple apples
I... (8 Replies)
Discussion started by: demmel
8 Replies
LEARN ABOUT NETBSD
zegrep
ZGREP(1) BSD General Commands Manual ZGREP(1)NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD December 28, 2003 BSD