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Full Discussion: Using variable inside awk
Top Forums Shell Programming and Scripting Using variable inside awk Post 302341594 by rdhanek on Thursday 6th of August 2009 08:45:21 AM
Old 08-06-2009
i am getting the error as follows. I am able to echo the result of the variable express correctly.
Code:
08/06/2009 07
test.sh: line 22: syntax error near unexpected token `else'
test.sh: line 22: `else'

 

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LEARN ABOUT PHP

tidy_error_count

TIDY_ERROR_COUNT(3)							 1						       TIDY_ERROR_COUNT(3)

tidy_error_count - Returns the Number of Tidy errors encountered for specified document

SYNOPSIS

       int tidy_error_count (tidy  $object)

DESCRIPTION

	Returns the number of Tidy errors encountered for the specified document.

PARAMETERS

	      o $object
		- The Tidy object.

RETURN VALUES

	Returns the number of errors.

EXAMPLES

       Example #1

	      tidy_error_count(3) example

	      <?php
	      $html = '<p>test</i>
	      <bogustag>bogus</bogustag>';

	      $tidy = tidy_parse_string($html);

	      echo tidy_error_count($tidy) . "
"; //1

	      echo $tidy->errorBuffer;
	      ?>

	      The above example will output:

	      1
	      line 1 column 1 - Warning: missing <!DOCTYPE> declaration
	      line 1 column 8 - Warning: discarding unexpected </i>
	      line 2 column 1 - Error: <bogustag> is not recognized!
	      line 2 column 1 - Warning: discarding unexpected <bogustag>
	      line 2 column 16 - Warning: discarding unexpected </bogustag>
	      line 1 column 1 - Warning: inserting missing 'title' element

SEE ALSO 
tidy_access_count(3), tidy_warning_count(3).
PHP Documentation Group 												       TIDY_ERROR_COUNT(3)
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