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Top Forums Shell Programming and Scripting don't understand a command "." Post 302341194 by Moumou on Wednesday 5th of August 2009 08:44:23 AM
Old 08-05-2009
don't understand a command "."

Hi all,

I have a script with those two lines :
Code:
test -f $PWD/mysetup.txt
. $PWD/mysetup.txt

I understand the first one, but could anyone explain me the role of the second one? All the thing I find is the usage :
Quote:
.: usage: . filename [argument]

Thx in advance
 

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PWD(1)							    BSD General Commands Manual 						    PWD(1)

NAME
pwd -- return working directory name SYNOPSIS
pwd [-L | -P] DESCRIPTION
The pwd utility writes the absolute pathname of the current working directory to the standard output. Some shells may provide a builtin pwd command which is similar or identical to this utility. Consult the builtin(1) manual page. The options are as follows: -L Display the logical current working directory. -P Display the physical current working directory (all symbolic links resolved). If no options are specified, the -L option is assumed. ENVIRONMENT
Environment variables used by pwd: PWD Logical current working directory. EXIT STATUS
The pwd utility exits 0 on success, and >0 if an error occurs. SEE ALSO
builtin(1), cd(1), csh(1), sh(1), getcwd(3) STANDARDS
The pwd utility conforms to IEEE Std 1003.1-2001 (``POSIX.1''). BUGS
In csh(1) the command dirs is always faster because it is built into that shell. However, it can give a different answer in the rare case that the current directory or a containing directory was moved after the shell descended into it. The -L option does not work unless the PWD environment variable is exported by the shell. BSD
April 12, 2003 BSD
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