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Top Forums Shell Programming and Scripting how to get fully qualified path name Post 302340654 by Franklin52 on Tuesday 4th of August 2009 06:43:44 AM
Old 08-04-2009
Try something like:

Code:
full=$(pwd)${1#.}
echo $full

Regards
 

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PWD(1)								   User Commands							    PWD(1)

NAME
pwd - print name of current/working directory SYNOPSIS
pwd [OPTION]... DESCRIPTION
Print the full filename of the current working directory. -L, --logical use PWD from environment, even if it contains symlinks -P, --physical avoid all symlinks --help display this help and exit --version output version information and exit NOTE: your shell may have its own version of pwd, which usually supersedes the version described here. Please refer to your shell's docu- mentation for details about the options it supports. GNU coreutils online help: <http://www.gnu.org/software/coreutils/> Report pwd translation bugs to <http://translationproject.org/team/> AUTHOR
Written by Jim Meyering. COPYRIGHT
Copyright (C) 2013 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>. This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. SEE ALSO
getcwd(3) The full documentation for pwd is maintained as a Texinfo manual. If the info and pwd programs are properly installed at your site, the command info coreutils 'pwd invocation' should give you access to the complete manual. GNU coreutils 8.22 June 2014 PWD(1)
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