Hello again.
I'm trying to use BC to calculate some numbers in a shell script.
I want to have the numbers rounded off to 1 decimal place.
for example:
initsize=1566720
zipsize=4733
I'm trying to get the ratio between them. the equation is:
(($initsize-$zipsize)/$initsize)*100
so... (3 Replies)
Hello,
I searched a lot on this Forum.
Please help me with the below problem.
I want to divide two numbers and the result should be the next nearest whole number.
E.G. Dividing 10.8/5 ideally gives 2.16. But the result should be 3 i.e. rounded off to the next whole number.
Any help will... (2 Replies)
Hello
I am getting this very annoying issue in awk:
awk '{a=12825;b=a*1.25; print b}' test
16031.2
Thing is the multiplication result is wrong... Result should be 16031.25.
I think the issue only happens on bigger numbers.
What can I do to get passed this?
Thanks by advance (3 Replies)
I need some help with my rouding script. I have started pretty much from scratch and have no idea if its correct or even close but I have been trying and have gotten to this point. i keep getting syntax errors and im not sure what is wrong. Here is what I got
let value=$1;
while
do
let... (4 Replies)
Hi,
I have managed to round up numbers by using the following command:
echo "5.54" | awk '{printf "%.0f\n", $1}'
result
6
How can I round up all the numbers in a column in a file and print the lines with the new calculated totals?
Thanks, (3 Replies)
I had a person bring an interesting problem to me that appears to involve some sort of rounding inside awk. I've verified this with awk and nawk on Solaris as well as with gawk 3.1.5 on a Linux box.
The original code fragment he brought me was thus:
for (index=0; index < 1; index=index+.1)
... (4 Replies)
I have some calculation in my script which is similar to the below example . I find that sometimes when using large decimal digits, the output gets automatically rounded off and it is affecting the program. I am not able to understand what is happening here..
awk '{
a=6.32498922
a1=6.324... (5 Replies)
Hi guys,
could someone throw some light on the following behaviour of printf (I'll start with info about the system and the tool/shell/interpreter versions)?:
$ uname -a
Linux linux-86if.site 3.1.0-1.2-desktop #1 SMP PREEMPT Thu Nov 3 14:45:45 UTC 2011 (187dde0) x86_64 x86_64 x86_64... (9 Replies)
Hi All,
I am using the below script which has awk command, but it is not returing the expected result. can some pls help me to correct the command.
The below script sample.ksh should give the result if the value of last 4 digits in the variable NM matches with the variable value DAT. The... (7 Replies)
Heyas
Trying to calculate the total size of a file by reading its bitrate.
Code snippet:
fs_expected() { #
# Returns the expected filesize in bytes
#
pr_str() {
ff=$(cat $TMP.info)
d="${ff#*bitrate: }"
echo "${d%%,*}" | $AWK '{print $1}' | head -n 1
}
t_BYTERATE=$((... (9 Replies)
Discussion started by: sea
9 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)