07-28-2009
date caculation
Hi Experts,
i have a variable in which i am giving date as user input
a=20090728
How can i addd or substract no of days from that date and get the required day.
lets say if i will add 4 days it should show 20090801
my operating system is SunOs
Thanks,
Subhendu
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LEARN ABOUT DEBIAN
lchage
lchage(8) System Manager's Manual lchage(8)
NAME
lchage - Display or change user password policy
SYNOPSIS
lchage [OPTION]... user
DESCRIPTION
Displays or allows changing password policy of user.
OPTIONS
-d, --date=days
Set the date of last password change to days after Jan 1 1970.
-E, --expire=days
Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration.
-i, --interactive
Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration.
-I, --inactive=days
Disable the account after days after password expires (after the user user is required to change the password).
-l, --list
Only list current user's policy and make no changes.
-m, --mindays=days
Require at least days days between password changes. Set days to 0 to disable this checking.
-M, --maxdays=days
Require changing the password after days since last password change. Set days to 99999 to disable this checking.
-W, --warndays=days
Start warning the user days before password expires (before the user is required to change the password).
EXIT STATUS
The exit status is 0 on success, nonzero on error.
libuser Jan 12 2005 lchage(8)