07-28-2009
date caculation
Hi Experts,
i have a variable in which i am giving date as user input
a=20090728
How can i addd or substract no of days from that date and get the required day.
lets say if i will add 4 days it should show 20090801
my operating system is SunOs
Thanks,
Subhendu
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
Hi all,
I've used various scripts in the past to work out the date last week from the current date, however I now have a need to work out the date 1 week from a given date.
So for example, if I have a date of the 23rd July 2010, I would like a script that can work out that one week back was... (4 Replies)
Discussion started by: Donkey25
4 Replies
2. UNIX for Dummies Questions & Answers
Hello gurus,
I am hoping someone can help me with the required code/script to make this work. I have the following file with records starting at line 4:
NETW~US60~000000000013220694~002~~IT~USD~2.24~20110201~99991231~01~01~20101104~... (4 Replies)
Discussion started by: chumsky
4 Replies
3. Shell Programming and Scripting
hi there
I have file names in different format as below
triss_20111117_fxcb.csv
triss_fxcb_20111117.csv
xpnl_hypo_reu_miplvdone_11172011.csv
xpnl_hypo_reu_miplvdone_11-17-2011.csv
xpnl_hypo_reu_miplvdone_20111117.csv
xpnl_hypo_reu_miplvdone_20111117xfb.csv... (10 Replies)
Discussion started by: manas_ranjan
10 Replies
4. Shell Programming and Scripting
Hi,
In a field, I should receive the date with time stamp in a particular field. But sometimes the vendor sends just the date or the timestamp or correctl the date×tamp. I have to figure out the the data is a date or time stamp or date×tamp.
If it is date then append "<space>00:00:00"... (1 Reply)
Discussion started by: machomaddy
1 Replies
5. Shell Programming and Scripting
Dear all,
I have 2 questions.
I have a file with many rows which has date of the format YYYYMMDD.
1. I need to change the date to that weeks friday date(Ex: 20120716(monday) to 20120720). Satuday/Sunday has to be changed to next week friday date too.
2. After converting the date to... (10 Replies)
Discussion started by: 2001.arun
10 Replies
6. Shell Programming and Scripting
I have file listed like below
-rw-r--r--+ 1 test test 17M Nov 26 14:43 test1.gz
-rw-r--r--+ 1 test test 0 Nov 26 14:44 test2.gz
-rw-r--r--+ 1 test test 0 Nov 27 10:41 test3.gz
-rw-r--r--+ 1 test test 244K Nov 27 10:41 test4.gz
-rw-r--r--+ 1 test test 17M Nov 27 10:41 test5.gz
I... (5 Replies)
Discussion started by: krish2014
5 Replies
7. Shell Programming and Scripting
i try to set linux date & time in specific format but it keep giving me error
Example :
date "+%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
or
date +"%d-%m-%C%y %H:%M:%S" -d "19-01-2017 00:05:01"
keep giving me this error :
date: invalid date ‘19-01-2017 00:05:01'
Please use CODE tags... (7 Replies)
Discussion started by: umen
7 Replies
8. UNIX for Beginners Questions & Answers
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
Discussion started by: Stuti
2 Replies
9. Answers to Frequently Asked Questions
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
10. Linux
Hi,
My question is how to calculate the quarter end date according to the current date in shell script? (2 Replies)
Discussion started by: Divya_1234
2 Replies
CHAGE(1) User Commands CHAGE(1)
NAME
chage - change user password expiry information
SYNOPSIS
chage [options] LOGIN
DESCRIPTION
The chage command changes the number of days between password changes and the date of the last password change. This information is used by
the system to determine when a user must change his/her password.
OPTIONS
The options which apply to the chage command are:
-d, --lastday LAST_DAY
Set the number of days since January 1st, 1970 when the password was last changed. The date may also be expressed in the format
YYYY-MM-DD (or the format more commonly used in your area).
-E, --expiredate EXPIRE_DATE
Set the date or number of days since January 1, 1970 on which the user's account will no longer be accessible. The date may also be
expressed in the format YYYY-MM-DD (or the format more commonly used in your area). A user whose account is locked must contact the
system administrator before being able to use the system again.
Passing the number -1 as the EXPIRE_DATE will remove an account expiration date.
-h, --help
Display help message and exit.
-I, --inactive INACTIVE
Set the number of days of inactivity after a password has expired before the account is locked. The INACTIVE option is the number of
days of inactivity. A user whose account is locked must contact the system administrator before being able to use the system again.
Passing the number -1 as the INACTIVE will remove an account's inactivity.
-l, --list
Show account aging information.
-m, --mindays MIN_DAYS
Set the minimum number of days between password changes to MIN_DAYS. A value of zero for this field indicates that the user may change
his/her password at any time.
-M, --maxdays MAX_DAYS
Set the maximum number of days during which a password is valid. When MAX_DAYS plus LAST_DAY is less than the current day, the user
will be required to change his/her password before being able to use his/her account. This occurrence can be planned for in advance by
use of the -W option, which provides the user with advance warning.
Passing the number -1 as MAX_DAYS will remove checking a password's validity.
-R, --root CHROOT_DIR
Apply changes in the CHROOT_DIR directory and use the configuration files from the CHROOT_DIR directory.
-W, --warndays WARN_DAYS
Set the number of days of warning before a password change is required. The WARN_DAYS option is the number of days prior to the
password expiring that a user will be warned his/her password is about to expire.
If none of the options are selected, chage operates in an interactive fashion, prompting the user with the current values for all of the
fields. Enter the new value to change the field, or leave the line blank to use the current value. The current value is displayed between a
pair of [ ] marks.
NOTE
The chage program requires a shadow password file to be available.
The chage command is restricted to the root user, except for the -l option, which may be used by an unprivileged user to determine when
his/her password or account is due to expire.
CONFIGURATION
The following configuration variables in /etc/login.defs change the behavior of this tool:
FILES
/etc/passwd
User account information.
/etc/shadow
Secure user account information.
EXIT VALUES
The chage command exits with the following values:
0
success
1
permission denied
2
invalid command syntax
15
can't find the shadow password file
SEE ALSO
passwd(5), shadow(5).
shadow-utils 4.1.5.1 05/25/2012 CHAGE(1)