07-26-2009
storing output from echo & cut into variable
Hi All,
Hope someone can advise here as I have been struggling to find a syntax that works here. I have tried a stack of combination I have seed in the forums but I think because I have needed to use "" and `` in the statments another method is found.
I am reading in lines with the following
10001:01234393923:0123447834834:01234482742:NNN:
The number of fields may differ between 3 and 17
I need to store the output from the following echo statements to a variable, but cannot seem to do it. When I execute this is works fine, I used echo to allow me to view each line that is being read in from a file I previously created.
echo $EachLine |cut -d":" -f1
echo $EachLine |cut -d":" -f`expr $COUNTER + 1`
Here is the code in context.
---
while read EachLine
do
COUNTER=1
while [ $COUNTER -le $NOPHONES ]
do
echo $EachLine
PHONEPOS=$COUNTER
echo $EachLine |cut -d":" -f1
echo $EachLine |cut -d":" -f`expr $COUNTER + 1`
COUNTER=`expr $COUNTER + 1`
# Output variables below in different order to file2.
#
# End of output to file2
done
done < file1.$$
Thanks in advance for any assistance.
Nigel...
---------- Post updated at 09:47 AM ---------- Previous update was at 09:27 AM ----------
I have managed to get one all but one of the statments working now. using
STRRECNO="`echo "$EachLine" |cut -d":" -f1`"
However the following line does not work I think still due to the `` but I
STRPHONENUM="`echo "$EachLine" |cut -d":" -f`expr $COUNTER + 1``"
Thanks for any help
Nigel...
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LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)