07-23-2009
Round Robin Distribution of Contents of file to 3 files
Hi
I need to create a script that distributes in round robin fashion the contents of a file to 3 files. The number of lines in a content of file can vary from 1-n(Each line is just a one letter word).The entire lines needs to get distributed into 3 files ( The order doesnt matter) , at the end of process the number of lines in each file should be more or less the same
eg
Input_file.txt
(Contents - 4 lines)
1
2
3
4
At the end of process
Op_1.txt
1
4
Op_2 .txt
2
Op_3.txt
3
Thanks for the help
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SHAR(1) BSD General Commands Manual SHAR(1)
NAME
shar -- create a shell archive of files
SYNOPSIS
shar file ...
DESCRIPTION
The shar command writes a sh(1) shell script to the standard output which will recreate the file hierarchy specified by the command line op-
erands. Directories will be recreated and must be specified before the files they contain (the find(1) utility does this correctly).
The shar command is normally used for distributing files by ftp(1) or mail(1).
EXAMPLES
To create a shell archive of the program ls(1) and mail it to Rick:
cd ls
shar `find . -print` | mail -s "ls source" rick
To recreate the program directory:
mkdir ls
cd ls
...
<delete header lines and examine mailed archive>
...
sh archive
SEE ALSO
compress(1), mail(1), tar(1), uuencode(1)
HISTORY
The shar command appeared in 4.4BSD.
BUGS
The shar command makes no provisions for special types of files or files containing magic characters. The shar command cannot handle files
without a newline ('
') as the last character.
It is easy to insert trojan horses into shar files. It is strongly recommended that all shell archive files be examined before running them
through sh(1). Archives produced using this implementation of shar may be easily examined with the command:
egrep -v '^[X#]' shar.file
BSD
June 6, 1993 BSD