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Top Forums Shell Programming and Scripting extracting part of a text file Post 302336333 by edidataguy on Tuesday 21st of July 2009 10:23:30 PM
Old 07-21-2009
Quote:
Originally Posted by dukessd
Or a nice simple grep would do it:

Code:
grep -E "12:01|12:02|12:03" <input_text_file_name> > <output_text_file_name>

So here we use the grep command to search for multiple "arguments", delimited by the pipe (|) symbol in the <input_text_file_name> and then redirect with the > to the <output_text_file_name> and then you should have the results you want in the <output_text_file_name> file.

pSeries and AIX Information Center

HTH
This may not meet all the requirements.
Remember the requirement says:
"""And not all lines in the log file start with a time stamp. Some lines are just random information about the server etc. But I want to extract those lines as well."""
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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