I need a non-perl (bash) way to strip the path from a list of "find" results. Below is the perl version which I could use, if I could figure out how to call the script with a variable (like in sh, $1 is the variable passed in ./script variable)
$file = "/path/to/file.txt";
# How do I... (2 Replies)
Hi All,
I am calling a perl program in my shell script as follows.
MY_IN_FILE=ABC.dat
MY_OUT_FILE=XYZ.dat
MY_VARIABLE="SomeValue"
perl mycode.pl $MY_IN_FILE > $MY_OUT_FILE
Question:-
Now I want to pass value of $MY_VARIABLE from script to perl... How do I do that? Can someone... (5 Replies)
Hi All,
I am learning PERL for one of the projects, and in one of these scripts, I read a flat text file and print in the terminal.
The problem is, the text file has a date field. The format is yyyymmdd. I need to display this as dd-mon-yyyy.
Any ideas to do this? Thanks a lot for the... (9 Replies)
Hi all,
i had a code where in user will enter a date in yyyymmdd format.. i didnt use any validation for the date and now the problem is if a user enters date instead of month after year it is proceeding with the code..
like if the date is 20120426 and if the user enters 20122604 it... (4 Replies)
I have an Excel 2007 excel sheet on windows machine and using
Spreadsheet::XLSX I had written a script to read the excel sheet and was successful.
My requirement is I need to generate another excel sheet from the old excel 2007 sheet on unix machine.
Now is it possible to read the excel... (2 Replies)
my $sysdate = strftime('%Y-%m-%d', localtime );
biDeriveByDate('Table_Str',$sysdate,\@lIndx,\@lResVals)
In a perl script, when I'm trying to pass $sysdate to some external function it's not working since $sysdate is passed as a string mentioned above but my function is expecting a date value... (1 Reply)
hello,
i have a lot of C old code I'm updating to C11 with tgmath.h for generic math. the old code has very specific types, real and complex, like cabsl, csinhl, etc
usually for simple bulk replacements i would do something simple like this
perl -pi -e 's/cosl/cos/g' *.c
the reference... (0 Replies)
Hi All,
I have line
,A,FDRM0002,12/21/2017,,0.961751583,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,
it contains date in mm/dd/yyyy format i want to change this to yyyymmdd format using perl.
Use code tags, thanks. (8 Replies)
The below perl script parses a variety of formats. If I use the numeric text file as input the script works correctly. However using the alpha text file as input there is a black output file. The portion in bold splits the field to parse f or NC_000023.10:g.153297761C>A into a variable $common but... (3 Replies)
Discussion started by: cmccabe
3 Replies
LEARN ABOUT PHP
datefmt_set_pattern
DATEFMT_SET_PATTERN(3) 1 DATEFMT_SET_PATTERN(3)IntlDateFormatter::setPattern - Set the pattern used for the IntlDateFormatter
Object oriented style
SYNOPSIS
public bool IntlDateFormatter::setPattern (string $pattern)
DESCRIPTION
Procedural style
bool datefmt_set_pattern (IntlDateFormatter $fmt, string $pattern)
Set the pattern used for the IntlDateFormatter.
PARAMETERS
o $fmt
- The formatter resource.
o $pattern
- New pattern string to use. Possible patterns are documented at http://userguide.icu-project.org/formatparse/datetime.
RETURN VALUES
Returns TRUE on success or FALSE on failure. Bad formatstrings are usually the cause of the failure.
EXAMPLES
Example #1
datefmt_set_pattern(3) example
<?php
$fmt = datefmt_create(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'First Formatted output with pattern is ' . datefmt_format($fmt, 0);
datefmt_set_pattern($fmt, 'yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . datefmt_get_pattern($fmt);
echo 'Second Formatted output with pattern is ' . datefmt_format($fmt, 0);
?>
Example #2
OO example
<?php
$fmt = new IntlDateFormatter(
'en_US',
IntlDateFormatter::FULL,IntlDateFormatter::FULL,
'America/Los_Angeles',
IntlDateFormatter::GREGORIAN,
'MM/dd/yyyy'
);
echo 'pattern of the formatter is : ' . $fmt->getPattern();
echo 'First Formatted output is ' . $fmt->format(0);
$fmt->setPattern('yyyymmdd hh:mm:ss z');
echo 'Now pattern of the formatter is : ' . $fmt->getPattern();
echo 'Second Formatted output is ' . $fmt->format(0);
?>
The above example will output:
pattern of the formatter is : MM/dd/yyyy
First Formatted output with pattern is 12/31/1969
Now pattern of the formatter is : yyyymmdd hh:mm:ss z
Second Formatted output with pattern is 19690031 04:00:00 PST
SEE ALSO datefmt_get_pattern(3), datefmt_create(3).
PHP Documentation Group DATEFMT_SET_PATTERN(3)