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Top Forums Shell Programming and Scripting Problem extracting just a part of a matching pattern Post 302334289 by lathavim on Wednesday 15th of July 2009 07:01:31 AM
Old 07-15-2009
Hi, See if this helps.

Code:
 
ls *.h >files_h
while read filename
do
grep "#define" $filename | cut -d " " -f2 >variables.lst
while read var_name
do
Used_Files=`grep $var_name *.c |cut -d ":" -f1`
echo $var_name >>output
echo "Defined in" $filename >>output
echo "Used in" $Used_Files >>output
done <variables.lst
done<files_h


Last edited by lathavim; 07-15-2009 at 08:10 AM..
 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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