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Full Discussion: date ranges
Top Forums Shell Programming and Scripting date ranges Post 302334239 by akil on Wednesday 15th of July 2009 05:13:34 AM
Old 07-15-2009
date ranges

Hi,
Please anyone help to achive this using perl or unix scripting .
Code:
This is date in my table 20090224,based on the date need to check the files,If file exist for that date then increment by 1 for that date and check till max date 'i.e.20090301 and push those files .
files1_20090224
files2_20090225
files3_20090226
files4_20090227
files4_20090228
files4_20090301

script :I am not sure how to handle the date addition and check.

echo "----------------------------------------------------------------------" >/Temp/a.log

$ORACLE_HOME/bin/sqlplus -S 'Username/password@DB1'<<! | tee -a >/Temp/a.log

SELECT TO_CHAR(START_DT,'YYYYMMDD') FROM test WHERE FREQ='D';

!

date=`awk NF a.log |egrep -iv 'to_char|-----'`

echo $date
.............
...........

Thanks ,
Akil
 

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DATETIME.SUB(3) 							 1							   DATETIME.SUB(3)

DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object

       Object oriented style

SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval) DESCRIPTION
Procedural style DateTime date_sub (DateTime $object, DateInterval $interval) Subtracts the specified DateInterval object from the specified DateTime object. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $interval - A DateInterval object RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. EXAMPLES
Example #1 DateTime.sub(3) example Object oriented style <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P10D')); echo $date->format('Y-m-d') . " "; ?> Procedural style <?php $date = date_create('2000-01-20'); date_sub($date, date_interval_create_from_date_string('10 days')); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2000-01-10 Example #2 Further DateTime.sub(3) examples <?php $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('PT10H30S')); echo $date->format('Y-m-d H:i:s') . " "; $date = new DateTime('2000-01-20'); $date->sub(new DateInterval('P7Y5M4DT4H3M2S')); echo $date->format('Y-m-d H:i:s') . " "; ?> The above example will output: 2000-01-19 13:59:30 1992-08-15 19:56:58 Example #3 Beware when subtracting months <?php $date = new DateTime('2001-04-30'); $interval = new DateInterval('P1M'); $date->sub($interval); echo $date->format('Y-m-d') . " "; $date->sub($interval); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-03-30 2001-03-02 NOTES
DateTime.modify(3) is an alternative when using PHP 5.2. SEE ALSO
DateTime.add(3), DateTime.diff(3), DateTime.modify(3). PHP Documentation Group DATETIME.SUB(3)
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