Hi,
I have writtena script that will recursivly go into subdirecotries and report out what files there are in there that have not been accessed over various date ranges.
I do this using a number of find commands:
find . -path './.snapshot' -prune -o -type f -atime -8
find... (4 Replies)
Hi All,
The developers want me to search and capture the weblogic log, you know this big logs of htmls.
They want to me to have ranges on the date and time. Like
from "2010-01-20 14:04:46,186" to "2010-01-20 15:00:12,490"
I can only do this,
cat /usr/local/bea/logs_prod1/debug.log |... (1 Reply)
Hi All,
The developers want me to search and capture the weblogic log, you know this big logs of htmls.
They want to me to have ranges on the date and time. Like
from "2010-01-20 14:04:46,186" to "2010-01-20 15:00:12,490"
I can only do this,
cat /usr/local/bea/logs_prod1/debug.log... (1 Reply)
I have a list of about 200,000 lines in a text file that look like this:
1 1 120
1 80 200
1 150 270
5 50 170
5 100 220
5 300 420
The first column is an identifier, the next 2 columns are a range (always 120 value range)
I'm trying fill in the values of those ranges, and remove... (4 Replies)
Good day to everyone!
So, let's start :)
I have a file with a numbers in some ranges
for example:
1 10
49 72
...
and this file need to transform to:
1
2
3
4 (14 Replies)
Hi,
I have two files
file1 chr1_22450_22500
chr2_12300_12350
chr1_34500_34550
file2 11000_13000
15000_19000
33000_44000
If the file 1 ranges fall between file2 ranges then assign the value of file2 in column 2 to file1
output:
chr2_12300_12350 11000_13000
chr1_34500_34550 ... (7 Replies)
Hi Guys,
I am having below tables used in oracle
bal
ID BALANCE BAL_DATE
1 -11.71 01-JAN-05 00.00.00
1 -405.71 02-JAN-05 00.00.00
1 -760.71 03-JAN-05 00.00.00
ref_table
PRODUCT EFF_FROM_DATE EFF_TO_DATE TYPE MIN_AMT MAX_AMT CHARGE
12 01-JAN-05 00.00.00 01-JAN-06... (6 Replies)
Hello,
I am a noob and need some help.
I am trying to find files created between a date range.
For Example:
These are files in directory.
-rw-r--r-- 1 user staff 6 May 8 09:43 file1.txt
-rw-r--r-- 1 user staff 6 May 8 09:43 file2.txt
-rw-r--r-- 1 user... (8 Replies)
Hi There, Good Day !!
I have txt file containing data in the below format. There are many lines, here i have mentioned for example.
cat remo.txt
2/3/2017 file1
3/4/2016 file2
6/6/2015 file5
1/1/2018 file3
4/3/2014 file4
-
-
-
I need to grep the file names for given date rage... (11 Replies)
Discussion started by: kumar85shiv
11 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)