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Top Forums Shell Programming and Scripting Grep for a pattern and print entire record Post 302332747 by aneesh e.p on Friday 10th of July 2009 03:14:10 AM
Old 07-10-2009
Java Grep for a pattern and print entire record

Dear Faiz,,


If the lines between the <LRECORD> </LRECORD> pair is unique you can use the -A and -B option of the grep command. For example in your post the lines b/w the<LRECORD> </LRECORD> pair is 1 so you can use the command:

grep 'f42' ./input.txt -A 2 -B 1

Hope this will help.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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