Hi Guys,
I was working some time ago n was in need to calculate date 30/31 days from today including Feb (Leap yr stuff). Today date is variable depending on day of execution of script. I tried searching but was not able to get exactly what I needed....So at that I time I implemented by my own which I have modified to generic so that it may helpful to you guys or somebody else like me in future...... Let me know if u find my problem with script
Last edited by coolgoose85; 07-09-2009 at 05:51 AM..
I need a script to figure out if a user's last login was 90 days or older. OS=AIX 5.3, shell=Korn
Here's what I have so far:
====
#!/usr/bin/ksh
NOW=`lsuser -a time_last_login root | awk -F= '{ print $2 }'`
(( LAST_LOGIN_TIME = 0 ))
(( DIFF = $NOW - $LAST_LOGIN_TIME ))
lsuser -a... (3 Replies)
I am a newbie to scripting.
I need a korn shell script to copy log files of current day to archive folder and rename with current days date stamp.
I would really appreciate your help.
File structure is as follows. Everyday files get overwritten, so I need copy to a archive directory and... (3 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am unable to get this KSH script to work. Can someone help. I've been told this should work with KSH93. Which I think I have on Solaris 10.
If I do a grep -i version /usr/dt/bin/dtksh I get
@(#)Version M-12/28/93d
@(#)Version 12/28/93
@(#)Version M-12/28/93
This is correct for... (5 Replies)
I wrote the day calculator also in bash. I would like to now, that is it good so?
#!/bin/bash
datum1=`date -d "1991/1/1" "+%s"`
datum2=`date "+%s"`
diff=$(($datum2-$datum1))
days=$(($diff/(60*60*24)))
echo $days
Thanks in advance for your help! (3 Replies)
Hi,
One of my Unix scripts needs to look for files coming in on Fridays. This script runs on Mondays. $date +"%y%m%d" will give me today's date. How can I get previous Friday's date.. can I do "today's date minus 3 days" to get Friday's date? If not, then any other way?? Name of the files is... (4 Replies)
hello,
can someone please suggest a script to rename a file that was generated today and filename that being generated daily starts with date, its a xml file.
here is example.
# find . -type f -mtime -1
./20130529_4995733057260357019.xml
#
this finename should be renamed to this format.... (6 Replies)
I am trying to get last 5 business day .
trying
for d in Mon Tue Wed Thu Fri
do
date +%Y%m%d -d "last $d"
done
gives me date
Thu Oct 20 23:56:26 EDT 2016
20161017
20161018
20161019
20161013
20161014
expected output should be
20161017
20161018
20161019
20161020 (2 Replies)
Hi Community!
Following on from this code in another thread:
#!/bin/bash
file_string=`/bin/cat date.txt | /usr/bin/awk '{print $5,$4,$7,$6,$8}'`
file_date=`/bin/date -d "$file_string"`
file_epoch=`/bin/date -d "$file_string" +%s`
now_epoch=`/bin/date +%s`
if
then
#let... (2 Replies)
Discussion started by: Greenage
2 Replies
LEARN ABOUT OSX
ncal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal, ncal -- displays a calendar and the date of easter
SYNOPSIS
cal [-jy] [[month] year]
cal [-j] -m month [year]
ncal [-jJpwy] [-s country_code] [[month] year]
ncal [-Jeo] [year]
DESCRIPTION
The cal utility displays a simple calendar in traditional format and ncal offers an alternative layout, more options and the date of easter.
The new format is a little cramped but it makes a year fit on a 25x80 terminal. If arguments are not specified, the current month is dis-
played.
The options are as follows:
-J Display Julian Calendar, if combined with the -e option, display date of easter according to the Julian Calendar.
-e Display date of easter (for western churches).
-j Display Julian days (days one-based, numbered from January 1).
-m month
Display the specified month.
-o Display date of orthodox easter (Greek and Russian Orthodox Churches).
-p Print the country codes and switching days from Julian to Gregorian Calendar as they are assumed by ncal. The country code as deter-
mined from the local environment is marked with an asterisk.
-s country_code
Assume the switch from Julian to Gregorian Calendar at the date associated with the country_code. If not specified, ncal tries to
guess the switch date from the local environment or falls back to September 2, 1752. This was when Great Britain and her colonies
switched to the Gregorian Calendar.
-w Print the number of the week below each week column.
-y Display a calendar for the specified year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month and year; the month is either a number between 1 and 12, or a full or abbreviated name as
specified by the current locale. Month and year default to those of the current system clock and time zone (so ``cal -m 8'' will display a
calendar for the month of August in the current year).
A year starts on Jan 1.
SEE ALSO calendar(3), strftime(3)HISTORY
A cal command appeared in Version 5 AT&T UNIX. The ncal command appeared in FreeBSD 2.2.6.
AUTHORS
The ncal command and manual were written by Wolfgang Helbig <helbig@FreeBSD.org>.
BUGS
The assignment of Julian--Gregorian switching dates to country codes is historically naive for many countries.
BSD November 23, 2004 BSD