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Top Forums Shell Programming and Scripting A little help using grep for anagram solving with BASH Post 302332340 by Donthommo on Thursday 9th of July 2009 04:19:35 AM
Old 07-09-2009
Homework? Ha no homework is quite a few years behind me!

Just an exercise I've set myself to revise my shell scripting because i've got interviews coming up.

Thanks for the reply, i'll take a proper look in the morning at the office, have to get to sleep soon.

If anyone has any thoughts on other variations on my idea that might work i'd like to hear them, i'll have another crack at finishing it in the next couple days when i'm done with loadrunner.

---------- Post updated at 09:19 AM ---------- Previous update was at 12:19 AM ----------

Thanks for the reply Perderabo, I tried running your script to see how it functioned but without success, I have not used sed before so not really ideal for helping me revise my scripting knowledge (which is of a fairly basic standard), but thankyou none the less for taking the time to reply.

What I was really after was just an idea of either an option for Grep that I had not thought of or suggestions on how one might go about removing the words from the final temp file that contain extra characters that are not wanted.

I.e. you want to find solutions for the letters 'nma' and you get:
Man
Manager
Mandate
etc etc

Of course the only actual one you want is 'Man' but the others appear because they still contain all the letters...

I'll see what I can come up with today but any thoughts/discussion on the subject is welcome and hopefully I can expand my knowledge a little by getting involved with the online community.

EDIT:


Came up with an idea, I'm going to try something along the lines of:

Load all the letters of the alphabet into an array.
Remove those contained in the user entered variable.
Remove any words from the word list that contain letters left in the array.

In theory this should just leave words contain all the input letters and no others. I still need to work out something for double letters but i'll work on that later.

This way also should take away the need to have it create so many temp files to ween down the results...

Last edited by Donthommo; 07-09-2009 at 05:42 AM..
 

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look(1) 							   User Commands							   look(1)

NAME
look - find words in the system dictionary or lines in a sorted list SYNOPSIS
/usr/bin/look [-d] [-f] [-tc] string [filename] DESCRIPTION
The look command consults a sorted filename and prints all lines that begin with string. If no filename is specified, look uses /usr/share/lib/dict/words with collating sequence -df. look limits the length of a word to search for to 256 characters. OPTIONS
-d Dictionary order. Only letters, digits, TAB and SPACE characters are used in comparisons. -f Fold case. Upper case letters are not distinguished from lower case in comparisons. -tc Set termination character. All characters to the right of c in string are ignored. FILES
/usr/share/lib/dict/words spelling list ATTRIBUTES
See attributes(5) for descriptions of the following attributes: +-----------------------------+-----------------------------+ | ATTRIBUTE TYPE | ATTRIBUTE VALUE | +-----------------------------+-----------------------------+ |Availability |SUNWesu | +-----------------------------+-----------------------------+ SEE ALSO
grep(1), sort(1), attributes(5) SunOS 5.11 29 Mar 1994 look(1)
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