Sponsored Content
Full Discussion: Command Line Argument
Top Forums Programming Command Line Argument Post 302332317 by pludi on Wednesday 8th of July 2009 05:27:58 PM
Old 07-08-2009
The shell is expanding the asterisk to the files in the current directory. Similar expansion happens with ?, shell variables, and character classes '[..]'. Standard behavior for all proper UNIX shells.

Use '*' instead if you want to pass a literal asterisk.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

array as command line argument !!!!

hello, can any help me how to can pass array as command line argument in korn shell. also how to read a array from command line. thanks spandu (2 Replies)
Discussion started by: spandu
2 Replies

2. Shell Programming and Scripting

How to get the value in last command line argument???

Say I want to get the value of last command line argument using the value in $# (or some other way if u can suggest) how do I do it?? $"$#" `$"$#"` These don't work :( (4 Replies)
Discussion started by: amit_oddey21
4 Replies

3. Shell Programming and Scripting

assign a command line argument and a unix command to awk variables

Hi , I have a piece of code ...wherein I need to assign the following ... 1) A command line argument to a variable e.g origCount=ARGV 2) A unix command to a variable e.g result=`wc -l testFile.txt` in my awk shell script When I do this : print "origCount" origCount --> I get the... (0 Replies)
Discussion started by: sweta_doshi
0 Replies

4. Shell Programming and Scripting

Need Help with the argument passing Through Command line

$$$$$ (5 Replies)
Discussion started by: asirohi
5 Replies

5. Shell Programming and Scripting

finding * in command line argument

I have to write a script to determine whether given command line argument ($1) contains "*" symbol or not, if $1 does not contains "*" symbol add it to $1, otherwise show message "Symbol is not required". For e.g. If we called this script q5 then after giving , $ q5 /bin Here $1 is /bin, it... (5 Replies)
Discussion started by: cynosure2009
5 Replies

6. Shell Programming and Scripting

command-line line 0: Missing yes/no argument

Hi Guys When I run the below command ssh -o 'PasswordAuthentication yes' -o 'PreferredAuthentications publickey' -i $HOME/.ssh/id_dsa Server_Name I found the below error ommand-line line 0: Missing yes/no argument Kindly help me to sort out Double post, continued... (0 Replies)
Discussion started by: Pratik4891
0 Replies

7. Shell Programming and Scripting

Help on command line argument in csh

HI , I am new to csh. I need to pass some command line arguments like ./abc.sh -os Linux -path abc -tl aa -PILX 1 I have defined the loop as shown below. But its taking "-os" switches as arguments. Its treating them as arguments. How to resolve it? while ( $#argv != 0 ) switch ($argv) ... (7 Replies)
Discussion started by: vineet.dhingra
7 Replies

8. Shell Programming and Scripting

Can a string be a command line argument?

I would like to use a string as a command line argument...is this possible using TCSH? For example say my script is called TEST and I would like to pass a string into my script stating why the test failed. EXAMPLE: TEST "Failed due to missing statement" (4 Replies)
Discussion started by: thibodc
4 Replies

9. Shell Programming and Scripting

Specify an entire UNIX command as a command line argument

I'm trying to write a bash script called YN that looks like the following YN "Specify a question" "doThis" "doThat" where "doThis" will be executed if the answer is "y", otherwise "doThat". For example YN "Do you want to list the file dog?" "ls -al dog" "" Here's my attempt... (3 Replies)
Discussion started by: LeoKSimon
3 Replies

10. UNIX for Beginners Questions & Answers

Command line argument

Hi Guys, I'm trying to work out how to add a command line argument inside single quotes. Would anyone be able to help please as I'm going mad :) I want to be able to place the filename on command line and it then be used in a script but it needs to have quotes surrounding it. Thanks in... (4 Replies)
Discussion started by: mutley2202
4 Replies
Perl::Critic::Command(3)				User Contributed Perl Documentation				  Perl::Critic::Command(3)

NAME
Perl::Critic::Command - Guts of perlcritic. SYNOPSIS
use Perl::Critic::Command qw< run >; local @ARGV = qw< --statistics-only lib bin >; run(); DESCRIPTION
This is the implementation of the perlcritic command. You can use this to run the command without going through a command interpreter. INTERFACE SUPPORT
This is considered to be a public class. However, its interface is experimental, and will likely change. IMPORTABLE SUBROUTINES
"run()" Does the equivalent of the perlcritic command. Unfortunately, at present, this doesn't take any parameters but uses @ARGV to get its input instead. Count on this changing; don't count on the current interface. TO DO
Make "run()" take parameters. The equivalent of @ARGV should be passed as a reference. Turn this into an object. AUTHOR
Jeffrey Ryan Thalhammer <jeff@imaginative-software.com> COPYRIGHT
Copyright (c) 2005-2011 Imaginative Software Systems. All rights reserved. This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself. The full text of this license can be found in the LICENSE file included with this module. perl v5.16.3 2014-06-09 Perl::Critic::Command(3)
All times are GMT -4. The time now is 02:10 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy