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Top Forums Shell Programming and Scripting Manipulating Pick multi dimensional data with awk. Post 302332033 by mike.strategis on Wednesday 8th of July 2009 03:03:45 AM
Old 07-08-2009
Manipulating Pick multi dimensional data with awk.

Hi.
I am reasonably new to awk, but have done quite a lot of unix scripting in the past. I have resolved the issues below with unix scripting but it runs like a dog. Moved to awk for speed and functionality but running up a big learning curve in a hurry, so hope there is some help here.

I am doing some data manipulation using awk and am having trouble with a couple of functions. I thought I would try here for some advice.

The data file that I am working with is from a Pick database, so has fields with comma delimiters, then within a field there can be more (subvariable) data separated by square bracket delimiters (]).

The data (for this example) is basically a quantity / price data file.
An example is.

DEVICES,DESCRIPTION OF DEVICES,24]99]499]999]2999]99999,22.35]21.60]19.85]18.35]17.62]16.00
BAGS,DESCRIPTION OF BAGS,24]99]499]999]4999]99999,
ITEMS,DESCRIPTION OF CARS,24]99]499]999]2999]99999,]]]]17.62]0.00
BAGS,DESCRIPTION OF BAGS,24]99]499]999]4999]99999,12.30]]


I am trying to achieve a flat file with all fields in it, comma separated.

So far I can split out the fields correctly

awk 'BEGIN { FS="," ; OFS="," ;} \
{
split($3,QTY,"]")
split($4,PR,"]")
} \

{ if (PR[1]=="")
{PR[1]=0 }
}\
{ if (PR[2]=="")
{PR[2]=0 }
}\
{ if (PR[3]=="")
{PR[3]=0 }
}\
{ if (PR[4]=="")
{PR[4]=0 }
}\
{ if (PR[5]=="")
{PR[5]=0 }
}\
{ if (PR[6]=="")
{PR[6]=0 }
}\
{ print $1,$2,QTY[1],QTY[2],QTY[3],QTY[4],QTY[5],QTY[6],PR[1],PR[2],PR[3],PR[4],PR[5],PR[6] }'\
file1.csv > file2.csv

Issue 1
This delivers a correct file output if the original line had a full complement of data, like lines 1 and 3 above. However it fails for line 2, because there is nothing in $4.
I want to check if $4 exists for a line, and if not replace the PR fields with a zero.

Issue 2
Sometimes the $4 will have less than six fields. Therefore I want to count the number of fields in $4 and append zero value fields to pad it out.

Issue 3
Obviously the series of if statements above isn't very elegant. Ideally I would like to do that in a loop where I count the number of fields and check them all sequentially.

Hope there is someone who likes this sort of challenge!!
 

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JOIN(1) 						      General Commands Manual							   JOIN(1)

NAME
join - relational database operator SYNOPSIS
join [ options ] file1 file2 DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If file1 is `-', the standard input is used. File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in each line. There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con- sists of the common field, then the rest of the line from file1, then the rest of the line from file2. Fields are normally separated by blank, tab or newline. In this case, multiple separators count as one, and leading separators are dis- carded. These options are recognized: -an In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2. -e s Replace empty output fields by string s. -jn m Join on the mth field of file n. If n is missing, use the mth field in each file. -o list Each output line comprises the fields specifed in list, each element of which has the form n.m, where n is a file number and m is a field number. -tc Use character c as a separator (tab character). Every appearance of c in a line is significant. SEE ALSO
sort(1), comm(1), awk(1) BUGS
With default field separation, the collating sequence is that of sort -b; with -t, the sequence is that of a plain sort. The conventions of join, sort, comm, uniq, look and awk(1) are wildly incongruous. JOIN(1)
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