I have a flat file and need to count no of records in the file less the header and the trailer record.
I would appreciate any and all asistance
Thanks
Hadi Lalani (2 Replies)
I've been working with an awk script and I'm wondeing id it's possible to count records in a file which DO NOT contain, in this instance fields 12 and 13.
With the one script I am wanting to display the count for the records WITH fields 12 and 13 and a seperate count of records WITHOUT fields... (2 Replies)
Hi every one;
I have a 31500-line text file upon which two following tasks are to be performed:
1: Rearranging the file
2: Taking the average of each column (considering number of zeros) and output the result into a new file
This is the code I've come up with:
awk '(NR%3150<3150)... (0 Replies)
Please find the below program. It contains the purpose of the program itself.
/* Program : Write a program to count the number of words in a given text file */
/* Date : 12-June-2010 */
# include <stdio.h>
# include <stdlib.h>
# include <string.h>
int main( int argc, char *argv )
{... (6 Replies)
Hi everyone.
I am a newbie to Linux stuff. I have this kind of problem which couldn't solve alone. I have a text file with records separated by empty lines like this:
ID: 20
Name: X
Age: 19
ID: 21
Name: Z
ID: 22
Email: xxx@yahoo.com
Name: Y
Age: 19
I want to grep records that... (4 Replies)
HI,
i have a file like this
t.txt
f1|_f2|_
f1|_f2|_
f1|_f2|_
as if col delimiter is |_ and row delimiter |_\n
trying to count number of records using awk
$ awk 'BEGIN{FS="|_" ; RS="~~\n"} {n++}END{print n} ' t.txt
7
wondering how can i count this to 3 ?
thx (9 Replies)
I have 2 files
"File 1" is delimited by ";" and "File 2" is delimited by "|".
File 1 below (3 record shown):
Doc1;03/01/2012;New York;6 Main Street;Mr. Smith 1;Mr. Jones
Doc2;03/01/2012;Syracuse;876 Broadway;John Davis;Barbara Lull
Doc3;03/01/2012;Buffalo;779 Old Windy Road;Charles... (2 Replies)
Hi Unix team,
I have a file with 30 columns with tab delimited. I need to count the records based on column 18 & 21 data.
So I cut the data from the file using
awk -F"\t" '{print $18,$21}' foo.txt
Following is the output:
USED SEDAN
USED SUV
NEW SUV
USED Truck
USED Truck
USED... (6 Replies)
Hi I am new to shell programming in unix
Please if I can provide help.
I have a file structure of a header record and "N" detail records.
The header record will be the total number of detail records
I need to split the file in 2:
One for the header
Another for all detail records
Could... (1 Reply)
Discussion started by: jamcogar
1 Replies
LEARN ABOUT V7
dh_installwm
DH_INSTALLWM(1) Debhelper DH_INSTALLWM(1)NAME
dh_installwm - register a window manager
SYNOPSIS
dh_installwm [debhelperoptions] [-n] [--priority=n] [wm...]
DESCRIPTION
dh_installwm is a debhelper program that is responsible for generating the postinst and prerm commands that register a window manager with
update-alternatives(8). The window manager's man page is also registered as a slave symlink (in v6 mode and up). It must be installed in
usr/share/man/man1/ in the package build directory prior to calling dh_installwm. In compat 9 and earlier, the manpage was optional.
FILES
debian/package.wm
List window manager programs to register.
OPTIONS --priority=n
Set the priority of the window manager. Default is 20, which is too low for most window managers; see the Debian Policy document for
instructions on calculating the correct value.
-n, --no-scripts
Do not modify postinst/prerm scripts. Turns this command into a no-op.
wm ...
Window manager programs to register.
NOTES
Note that this command is not idempotent. dh_prep(1) should be called between invocations of this command. Otherwise, it may cause multiple
instances of the same text to be added to maintainer scripts.
SEE ALSO debhelper(7)
This program is a part of debhelper.
AUTHOR
Joey Hess <joeyh@debian.org>
11.1.6ubuntu2 2018-05-10 DH_INSTALLWM(1)