07-06-2009
Help required with awk/sed
Hi
I have a file, with format like:
column1|coulumn2|column3|column4
A|X|K|18
L|O|R|31,42,25
G|H|I|55,66
L|E|Q|25,31,94
output required:
column1|coulumn2|column3|column4
A|X|K|18
L|O|R|31,25
L|E|Q|25,31
Input File Format: All columns are seperated using |, last column might have multiple values spearated with ,
Output file rules:
1. Only keep rows which has one of the 18,25 or 31 (in its comma separated values) in the last column's comma separated values.
2. if last column contains any of the 18,25,31 values and some any other number, then remove numbers other than 18,25,31 as in the example output file - 1st row remains as it is, in 2nd 42 removed as this does not belong to the set (18,25,31), 3rd line remove altoghther as this does not have any of the (18,25,31) in its comma seperaetd values, 4th row remains but 94 goes away.
Please help writing one liner using awk or sed.
Thanks.
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LEARN ABOUT FREEBSD
colrm
COLRM(1) BSD General Commands Manual COLRM(1)
NAME
colrm -- remove columns from a file
SYNOPSIS
colrm [start [stop]]
DESCRIPTION
The colrm utility removes selected columns from the lines of a file. A column is defined as a single character in a line. Input is read
from the standard input. Output is written to the standard output.
If only the start column is specified, columns numbered less than the start column will be written. If both start and stop columns are spec-
ified, columns numbered less than the start column or greater than the stop column will be written. Column numbering starts with one, not
zero.
Tab characters increment the column count to the next multiple of eight. Backspace characters decrement the column count by one.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of colrm as described in environ(7).
EXIT STATUS
The colrm utility exits 0 on success, and >0 if an error occurs.
SEE ALSO
awk(1), column(1), cut(1), paste(1)
HISTORY
The colrm command appeared in 3.0BSD.
BSD
August 4, 2004 BSD